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Merge bzr.dev to resolve news conflict

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        right = searchers[1].seen
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        return (left.difference(right), right.difference(left))
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    def find_descendants(self, old_key, new_key):
 
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        """Find descendants of old_key that are ancestors of new_key."""
 
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        child_map = self.get_child_map(self._find_descendant_ancestors(
 
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            old_key, new_key))
 
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        graph = Graph(DictParentsProvider(child_map))
 
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        searcher = graph._make_breadth_first_searcher([old_key])
 
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        list(searcher)
 
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        return searcher.seen
 
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    def _find_descendant_ancestors(self, old_key, new_key):
 
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        """Find ancestors of new_key that may be descendants of old_key."""
 
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        stop = self._make_breadth_first_searcher([old_key])
 
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        descendants = self._make_breadth_first_searcher([new_key])
 
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        for revisions in descendants:
 
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            old_stop = stop.seen.intersection(revisions)
 
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            descendants.stop_searching_any(old_stop)
 
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            seen_stop = descendants.find_seen_ancestors(stop.step())
 
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            descendants.stop_searching_any(seen_stop)
 
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        return descendants.seen.difference(stop.seen)
 
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    def get_child_map(self, keys):
 
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        """Get a mapping from parents to children of the specified keys.
 
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        This is simply the inversion of get_parent_map.  Only supplied keys
 
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        will be discovered as children.
 
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        :return: a dict of key:child_list for keys.
 
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        """
 
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        parent_map = self._parents_provider.get_parent_map(keys)
 
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        parent_child = {}
 
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        for child, parents in sorted(parent_map.items()):
 
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            for parent in parents:
 
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                parent_child.setdefault(parent, []).append(child)
 
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        return parent_child
 
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    def find_distance_to_null(self, target_revision_id, known_revision_ids):
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        """Find the left-hand distance to the NULL_REVISION.
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                stop.add(parent_id)
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        return found
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    def find_lefthand_merger(self, merged_key, tip_key):
 
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        """Find the first lefthand ancestor of tip_key that merged merged_key.
 
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        We do this by first finding the descendants of merged_key, then
 
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        walking through the lefthand ancestry of tip_key until we find a key
 
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        that doesn't descend from merged_key.  Its child is the key that
 
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        merged merged_key.
 
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        :return: The first lefthand ancestor of tip_key to merge merged_key.
 
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            merged_key if it is a lefthand ancestor of tip_key.
 
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            None if no ancestor of tip_key merged merged_key.
 
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        """
 
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        descendants = self.find_descendants(merged_key, tip_key)
 
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        candidate_iterator = self.iter_lefthand_ancestry(tip_key)
 
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        last_candidate = None
 
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        for candidate in candidate_iterator:
 
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            if candidate not in descendants:
 
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                return last_candidate
 
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            last_candidate = candidate
 
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    def find_unique_lca(self, left_revision, right_revision,
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                        count_steps=False):
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        """Find a unique LCA.
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                yield (ghost, None)
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            pending = next_pending
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    def iter_lefthand_ancestry(self, start_key, stop_keys=None):
 
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        if stop_keys is None:
 
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            stop_keys = ()
 
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        next_key = start_key
 
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        def get_parents(key):
 
981
            try:
 
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                return self._parents_provider.get_parent_map([key])[key]
 
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            except KeyError:
 
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                raise errors.RevisionNotPresent(next_key, self)
 
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        while True:
 
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            if next_key in stop_keys:
 
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                return
 
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            parents = get_parents(next_key)
 
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            yield next_key
 
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            if len(parents) == 0:
 
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                return
 
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            else:
 
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                next_key = parents[0]
 
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    def iter_topo_order(self, revisions):
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        """Iterate through the input revisions in topological order.
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