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# Copyright (C) 2005 Canonical Ltd
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
import errno
import os
import shutil
from bzrlib import (
bzrdir,
errors,
ui,
)
from bzrlib.osutils import isdir
from bzrlib.trace import note
from bzrlib.workingtree import WorkingTree
def is_detritus(subp):
"""Return True if the supplied path is detritus, False otherwise"""
return subp.endswith('.THIS') or subp.endswith('.BASE') or\
subp.endswith('.OTHER') or subp.endswith('~') or subp.endswith('.tmp')
def iter_deletables(tree, unknown=False, ignored=False, detritus=False):
"""Iterate through files that may be deleted"""
for subp in tree.extras():
if detritus and is_detritus(subp):
yield tree.abspath(subp), subp
continue
if tree.is_ignored(subp):
if ignored:
yield tree.abspath(subp), subp
else:
if unknown:
yield tree.abspath(subp), subp
def clean_tree(directory, unknown=False, ignored=False, detritus=False,
dry_run=False, no_prompt=False):
"""Remove files in the specified classes from the tree"""
tree = WorkingTree.open_containing(directory)[0]
tree.lock_read()
try:
deletables = list(iter_deletables(tree, unknown=unknown,
ignored=ignored, detritus=detritus))
deletables = _filter_out_nested_bzrdirs(deletables)
if len(deletables) == 0:
note('Nothing to delete.')
return 0
if not no_prompt:
for path, subp in deletables:
# FIXME using print is very bad idea
# clean_tree should accept to_file argument to write the output
print subp
val = raw_input('Are you sure you wish to delete these [y/N]?')
if val.lower() not in ('y', 'yes'):
print 'Canceled'
return 0
delete_items(deletables, dry_run=dry_run)
finally:
tree.unlock()
def _filter_out_nested_bzrdirs(deletables):
result = []
for path, subp in deletables:
# bzr won't recurse into unknowns/ignored directories by default
# so we don't pay a penalty for checking subdirs of path for nested
# bzrdir.
# That said we won't detect the branch in the subdir of non-branch
# directory and therefore delete it. (worth to FIXME?)
if isdir(path):
try:
bzrdir.BzrDir.open(path)
except errors.NotBranchError:
result.append((path,subp))
else:
# TODO may be we need to notify user about skipped directories?
pass
else:
result.append((path,subp))
return result
def delete_items(deletables, dry_run=False):
"""Delete files in the deletables iterable"""
def onerror(function, path, excinfo):
"""Show warning for errors seen by rmtree.
"""
# Handle only permission error while removing files.
# Other errors are re-raised.
if function is not os.remove or excinfo[1].errno != errno.EACCES:
raise
ui.ui_factory.show_warning('unable to remove %s' % path)
has_deleted = False
for path, subp in deletables:
if not has_deleted:
note("deleting paths:")
has_deleted = True
if not dry_run:
if isdir(path):
shutil.rmtree(path, onerror=onerror)
else:
try:
os.unlink(path)
note(' ' + subp)
except OSError, e:
# We handle only permission error here
if e.errno != errno.EACCES:
raise e
ui.ui_factory.show_warning(
'unable to remove "%s": %s.' % (path, e.strerror))
else:
note(' ' + subp)
if not has_deleted:
note("No files deleted.")
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