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# Copyright (C) 2006, 2007 Canonical Ltd
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
"""Blackbox tests for debugger breakin"""
import os
import signal
import subprocess
import sys
import time
from bzrlib import tests
class TestBreakin(tests.TestCase):
# FIXME: If something is broken, these tests may just hang indefinitely in
# wait() waiting for the child to exit when it's not going to.
def setUp(self):
if sys.platform == 'win32':
raise tests.TestSkipped('breakin signal not tested on win32')
super(TestBreakin, self).setUp()
def _dont_SIGQUIT_on_darwin(self):
if sys.platform == 'darwin':
# At least on Leopard and with python 2.6, this test will raise a
# popup window asking if the python failure should be reported to
# Apple... That's not the point of the test :) Marking the test as
# not applicable Until we find a way to disable that intrusive
# behavior... --vila20080611
raise tests.TestNotApplicable(
'%s raises a popup on OSX' % self.id())
# port 0 means to allocate any port
_test_process_args = ['serve', '--port', 'localhost:0']
def test_breakin(self):
# Break in to a debugger while bzr is running
# we need to test against a command that will wait for
# a while -- bzr serve should do
proc = self.start_bzr_subprocess(self._test_process_args,
env_changes=dict(BZR_SIGQUIT_PDB=None))
# wait for it to get started, and print the 'listening' line
proc.stderr.readline()
# first sigquit pops into debugger
os.kill(proc.pid, signal.SIGQUIT)
proc.stdin.write("q\n")
time.sleep(.5)
err = proc.stderr.readline()
self.assertContainsRe(err, r'entering debugger')
def test_breakin_harder(self):
self._dont_SIGQUIT_on_darwin()
proc = self.start_bzr_subprocess(self._test_process_args,
env_changes=dict(BZR_SIGQUIT_PDB=None))
# wait for it to get started, and print the 'listening' line
proc.stderr.readline()
# break into the debugger
os.kill(proc.pid, signal.SIGQUIT)
# now send a second sigquit, which should cause it to exit. That
# won't happen until the original signal has been noticed by the
# child and it's run its signal handler. We don't know quite how long
# this will take, but if it's more than 10s then it's probably not
# going to work.
for i in range(100):
time.sleep(0.1)
os.kill(proc.pid, signal.SIGQUIT)
# note: waitpid is different on win32, but this test only runs on
# unix
r = os.waitpid(proc.pid, os.WNOHANG)
if r != (0, 0):
# high bit says if core was dumped; we don't care
self.assertEquals(r[1] & 0x7f, signal.SIGQUIT)
break
else:
self.fail("subprocess wasn't terminated by repeated SIGQUIT")
def test_breakin_disabled(self):
self._dont_SIGQUIT_on_darwin()
proc = self.start_bzr_subprocess(self._test_process_args,
env_changes=dict(BZR_SIGQUIT_PDB='0'))
# wait for it to get started, and print the 'listening' line
proc.stderr.readline()
# first hit should just kill it
os.kill(proc.pid, signal.SIGQUIT)
proc.wait()
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