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# Copyright (C) 2008 Canonical Ltd
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
#
"""B+Tree index parsing."""
def _parse_leaf_lines(bytes, key_length, ref_list_length):
lines = bytes.split('\n')
nodes = []
for line in lines[1:]:
if line == '':
return nodes
elements = line.split('\0', key_length)
# keys are tuples
key = tuple(elements[:key_length])
line = elements[-1]
references, value = line.rsplit('\0', 1)
if ref_list_length:
ref_lists = []
for ref_string in references.split('\t'):
ref_lists.append(tuple([
tuple(ref.split('\0')) for ref in ref_string.split('\r') if ref
]))
ref_lists = tuple(ref_lists)
node_value = (value, ref_lists)
else:
node_value = (value, ())
nodes.append((key, node_value))
return nodes
def _flatten_node(node, reference_lists):
"""Convert a node into the serialized form.
:param node: A tuple representing a node (key_tuple, value, references)
:param reference_lists: Does this index have reference lists?
:return: (string_key, flattened)
string_key The serialized key for referencing this node
flattened A string with the serialized form for the contents
"""
if reference_lists:
# TODO: Consider turning this back into the 'unoptimized' nested loop
# form. It is probably more obvious for most people, and this is
# just a reference implementation.
flattened_references = ['\r'.join(['\x00'.join(reference)
for reference in ref_list])
for ref_list in node[3]]
else:
flattened_references = []
string_key = '\x00'.join(node[1])
line = ("%s\x00%s\x00%s\n" % (string_key,
'\t'.join(flattened_references), node[2]))
return string_key, line
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