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# Copyright (C) 2005 by Canonical Development Ltd
#
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
from StringIO import StringIO
from bzrlib.revisionspec import RevisionSpec
from bzrlib.status import show_pending_merges, show_tree_status
from bzrlib.tests import TestCaseWithTransport
class TestStatus(TestCaseWithTransport):
def test_pending_none(self):
# Test whether show_pending_merges works in a tree with no commits
tree = self.make_branch_and_tree('a')
tree.commit('empty commit')
tree2 = self.make_branch_and_tree('b')
# set a left most parent that is not a present commit
tree2.add_parent_tree_id('some-ghost', allow_leftmost_as_ghost=True)
# do a merge
tree2.merge_from_branch(tree.branch)
output = StringIO()
show_pending_merges(tree2, output)
self.assertContainsRe(output.getvalue(), 'empty commit')
def tests_revision_to_revision(self):
"""doing a status between two revision trees should work."""
tree = self.make_branch_and_tree('.')
r1_id = tree.commit('one', allow_pointless=True)
r2_id = tree.commit('two', allow_pointless=True)
r2_tree = tree.branch.repository.revision_tree(r2_id)
output = StringIO()
show_tree_status(tree, to_file=output,
revision=[RevisionSpec.from_string("revid:%s" % r1_id),
RevisionSpec.from_string("revid:%s" % r2_id)])
# return does not matter as long as it did not raise.
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