1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
|
# (C) 2005 Canonical
# This program is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 2 of the License, or
# (at your option) any later version.
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
import bzrlib.errors
class RevisionReference(object):
"""
Reference to a stored revision.
Includes the revision_id and revision_sha1.
"""
revision_id = None
revision_sha1 = None
def __init__(self, revision_id, revision_sha1=None):
if revision_id == None \
or isinstance(revision_id, basestring):
self.revision_id = revision_id
else:
raise ValueError('bad revision_id %r' % revision_id)
if revision_sha1 != None:
if isinstance(revision_sha1, basestring) \
and len(revision_sha1) == 40:
self.revision_sha1 = revision_sha1
else:
raise ValueError('bad revision_sha1 %r' % revision_sha1)
class Revision(object):
"""Single revision on a branch.
Revisions may know their revision_hash, but only once they've been
written out. This is not stored because you cannot write the hash
into the file it describes.
After bzr 0.0.5 revisions are allowed to have multiple parents.
parents
List of parent revisions, each is a RevisionReference.
"""
inventory_id = None
inventory_sha1 = None
revision_id = None
timestamp = None
message = None
timezone = None
committer = None
def __init__(self, **args):
self.__dict__.update(args)
self.parents = []
def __repr__(self):
return "<Revision id %s>" % self.revision_id
def __eq__(self, other):
if not isinstance(other, Revision):
return False
return (self.inventory_id == other.inventory_id
and self.inventory_sha1 == other.inventory_sha1
and self.revision_id == other.revision_id
and self.timestamp == other.timestamp
and self.message == other.message
and self.timezone == other.timezone
and self.committer == other.committer)
def __ne__(self, other):
return not self.__eq__(other)
REVISION_ID_RE = None
def validate_revision_id(rid):
"""Check rid is syntactically valid for a revision id."""
global REVISION_ID_RE
if not REVISION_ID_RE:
import re
REVISION_ID_RE = re.compile('[\w.-]+@[\w.-]+--?\d+--?[0-9a-f]+\Z')
if not REVISION_ID_RE.match(rid):
raise ValueError("malformed revision-id %r" % rid)
def is_ancestor(revision_id, candidate_id, revision_source):
"""Return true if candidate_id is an ancestor of revision_id.
A false negative will be returned if any intermediate descendent of
candidate_id is not present in any of the revision_sources.
revisions_source is an object supporting a get_revision operation that
behaves like Branch's.
"""
for ancestor_id, distance in iter_ancestors(revision_id, revision_source):
if ancestor_id == candidate_id:
return True
return False
def iter_ancestors(revision_id, revision_source, only_present=False):
ancestors = (revision_id,)
distance = 0
while len(ancestors) > 0:
new_ancestors = []
for ancestor in ancestors:
if not only_present:
yield ancestor, distance
try:
revision = revision_source.get_revision(ancestor)
except bzrlib.errors.NoSuchRevision, e:
if e.revision == revision_id:
raise
else:
continue
if only_present:
yield ancestor, distance
new_ancestors.extend([p.revision_id for p in revision.parents])
ancestors = new_ancestors
distance += 1
def find_present_ancestors(revision_id, revision_source):
"""Return the ancestors of a revision present in a branch.
It's possible that a branch won't have the complete ancestry of
one of its revisions.
"""
found_ancestors = {}
anc_iter = enumerate(iter_ancestors(revision_id, revision_source,
only_present=True))
for anc_order, (anc_id, anc_distance) in anc_iter:
if not found_ancestors.has_key(anc_id):
found_ancestors[anc_id] = (anc_order, anc_distance)
return found_ancestors
def __get_closest(intersection):
intersection.sort()
matches = []
for entry in intersection:
if entry[0] == intersection[0][0]:
matches.append(entry[2])
return matches
def common_ancestor(revision_a, revision_b, revision_source):
"""Find the ancestor common to both revisions that is closest to both.
"""
from bzrlib.trace import mutter
a_ancestors = find_present_ancestors(revision_a, revision_source)
b_ancestors = find_present_ancestors(revision_b, revision_source)
a_intersection = []
b_intersection = []
# a_order is used as a tie-breaker when two equally-good bases are found
for revision, (a_order, a_distance) in a_ancestors.iteritems():
if b_ancestors.has_key(revision):
a_intersection.append((a_distance, a_order, revision))
b_intersection.append((b_ancestors[revision][1], a_order, revision))
mutter("a intersection: %r" % a_intersection)
mutter("b intersection: %r" % b_intersection)
a_closest = __get_closest(a_intersection)
if len(a_closest) == 0:
return None
b_closest = __get_closest(b_intersection)
assert len(b_closest) != 0
mutter ("a_closest %r" % a_closest)
mutter ("b_closest %r" % b_closest)
if a_closest[0] in b_closest:
return a_closest[0]
elif b_closest[0] in a_closest:
return b_closest[0]
else:
raise bzrlib.errors.AmbiguousBase((a_closest[0], b_closest[0]))
return a_closest[0]
class MultipleRevisionSources(object):
"""Proxy that looks in multiple branches for revisions."""
def __init__(self, *args):
object.__init__(self)
assert len(args) != 0
self._revision_sources = args
def get_revision(self, revision_id):
for source in self._revision_sources:
try:
return source.get_revision(revision_id)
except bzrlib.errors.NoSuchRevision, e:
pass
raise e
def get_intervening_revisions(ancestor_id, rev_id, rev_source,
revision_history=None):
"""Find the longest line of descent from maybe_ancestor to revision.
Revision history is followed where possible.
If ancestor_id == rev_id, list will be empty.
Otherwise, rev_id will be the last entry. ancestor_id will never appear.
If ancestor_id is not an ancestor, NotAncestor will be thrown
"""
[rev_source.get_revision(r) for r in (ancestor_id, rev_id)]
if ancestor_id == rev_id:
return []
def historical_lines(line):
"""Return a tuple of historical/non_historical lines, for sorting.
The non_historical count is negative, since non_historical lines are
a bad thing.
"""
good_count = 0
bad_count = 0
for revision in line:
if revision in revision_history:
good_count += 1
else:
bad_count -= 1
return good_count, bad_count
active = [[rev_id]]
successful_lines = []
while len(active) > 0:
new_active = []
for line in active:
parent_ids = [p.revision_id for p in
rev_source.get_revision(line[-1]).parents]
for parent in parent_ids:
line_copy = line[:]
if parent == ancestor_id:
successful_lines.append(line_copy)
else:
line_copy.append(parent)
new_active.append(line_copy)
active = new_active
if len(successful_lines) == 0:
raise bzrlib.errors.NotAncestor(rev_id, ancestor_id)
for line in successful_lines:
line.reverse()
if revision_history is not None:
by_historical_lines = []
for line in successful_lines:
count = historical_lines(line)
by_historical_lines.append((count, line))
by_historical_lines.sort()
if by_historical_lines[-1][0][0] > 0:
return by_historical_lines[-1][1]
assert len(successful_lines)
successful_lines.sort(cmp, len)
return successful_lines[-1]
|