167
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if not REVISION_ID_RE.match(rid):
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raise ValueError("malformed revision-id %r" % rid)
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def is_ancestor(revision_id, candidate_id, revision_source):
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"""Return true if candidate_id is an ancestor of revision_id.
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A false negative will be returned if any intermediate descendent of
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candidate_id is not present in any of the revision_sources.
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revisions_source is an object supporting a get_revision operation that
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behaves like Branch's.
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for ancestor_id, distance in iter_ancestors(revision_id, revision_source):
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if ancestor_id == candidate_id:
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def iter_ancestors(revision_id, revision_source, only_present=False):
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ancestors = (revision_id,)
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while len(ancestors) > 0:
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for ancestor in ancestors:
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yield ancestor, distance
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revision = revision_source.get_revision(ancestor)
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except bzrlib.errors.NoSuchRevision, e:
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if e.revision == revision_id:
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yield ancestor, distance
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new_ancestors.extend([p.revision_id for p in revision.parents])
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ancestors = new_ancestors
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def find_present_ancestors(revision_id, revision_source):
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"""Return the ancestors of a revision present in a branch.
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It's possible that a branch won't have the complete ancestry of
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one of its revisions.
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anc_iter = enumerate(iter_ancestors(revision_id, revision_source,
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for anc_order, (anc_id, anc_distance) in anc_iter:
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if not found_ancestors.has_key(anc_id):
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found_ancestors[anc_id] = (anc_order, anc_distance)
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return found_ancestors
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def __get_closest(intersection):
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for entry in intersection:
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if entry[0] == intersection[0][0]:
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matches.append(entry[2])
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def common_ancestor(revision_a, revision_b, revision_source):
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"""Find the ancestor common to both revisions that is closest to both.
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from bzrlib.trace import mutter
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a_ancestors = find_present_ancestors(revision_a, revision_source)
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b_ancestors = find_present_ancestors(revision_b, revision_source)
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# a_order is used as a tie-breaker when two equally-good bases are found
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for revision, (a_order, a_distance) in a_ancestors.iteritems():
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if b_ancestors.has_key(revision):
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a_intersection.append((a_distance, a_order, revision))
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b_intersection.append((b_ancestors[revision][1], a_order, revision))
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mutter("a intersection: %r" % a_intersection)
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mutter("b intersection: %r" % b_intersection)
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a_closest = __get_closest(a_intersection)
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if len(a_closest) == 0:
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b_closest = __get_closest(b_intersection)
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assert len(b_closest) != 0
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mutter ("a_closest %r" % a_closest)
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mutter ("b_closest %r" % b_closest)
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if a_closest[0] in b_closest:
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elif b_closest[0] in a_closest:
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raise bzrlib.errors.AmbiguousBase((a_closest[0], b_closest[0]))
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class MultipleRevisionSources(object):
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"""Proxy that looks in multiple branches for revisions."""
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def __init__(self, *args):
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object.__init__(self)
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assert len(args) != 0
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self._revision_sources = args
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def get_revision(self, revision_id):
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for source in self._revision_sources:
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return source.get_revision(revision_id)
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except bzrlib.errors.NoSuchRevision, e:
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def get_intervening_revisions(ancestor_id, rev_id, rev_source,
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revision_history=None):
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"""Find the longest line of descent from maybe_ancestor to revision.
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Revision history is followed where possible.
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If ancestor_id == rev_id, list will be empty.
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Otherwise, rev_id will be the last entry. ancestor_id will never appear.
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If ancestor_id is not an ancestor, NotAncestor will be thrown
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[rev_source.get_revision(r) for r in (ancestor_id, rev_id)]
287
if ancestor_id == rev_id:
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def historical_lines(line):
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"""Return a tuple of historical/non_historical lines, for sorting.
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The non_historical count is negative, since non_historical lines are
296
for revision in line:
297
if revision in revision_history:
301
return good_count, bad_count
303
successful_lines = []
304
while len(active) > 0:
307
parent_ids = [p.revision_id for p in
308
rev_source.get_revision(line[-1]).parents]
309
for parent in parent_ids:
311
if parent == ancestor_id:
312
successful_lines.append(line_copy)
314
line_copy.append(parent)
315
new_active.append(line_copy)
317
if len(successful_lines) == 0:
318
raise bzrlib.errors.NotAncestor(rev_id, ancestor_id)
319
for line in successful_lines:
321
if revision_history is not None:
322
by_historical_lines = []
323
for line in successful_lines:
324
count = historical_lines(line)
325
by_historical_lines.append((count, line))
326
by_historical_lines.sort()
327
if by_historical_lines[-1][0][0] > 0:
328
return by_historical_lines[-1][1]
329
assert len(successful_lines)
330
successful_lines.sort(cmp, len)
331
return successful_lines[-1]