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# Copyright (C) 2006 Canonical Ltd
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
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"""Remove the last revision from the history of the current branch."""
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# TODO: make the guts of this methods on tree, branch.
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revision as _mod_revision,
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from bzrlib.branch import Branch
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from bzrlib.errors import BoundBranchOutOfDate
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def remove_tags(branch, graph, old_tip, new_tip):
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"""Remove tags on revisions between old_tip and new_tip.
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:param branch: Branch to remove tags from
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:param graph: Graph object for branch repository
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:param old_tip: Old branch tip
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:param new_tip: New branch tip
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:return: Names of the removed tags
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reverse_tags = branch.tags.get_reverse_tag_dict()
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ancestors = graph.find_unique_ancestors(old_tip, [new_tip])
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for revid, tags in reverse_tags.iteritems():
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if not revid in ancestors:
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branch.tags.delete_tag(tag)
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removed_tags.append(tag)
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def uncommit(branch, dry_run=False, verbose=False, revno=None, tree=None,
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local=False, keep_tags=False):
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"""Remove the last revision from the supplied branch.
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:param dry_run: Don't actually change anything
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:param verbose: Print each step as you do it
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:param revno: Remove back to this revision
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:param local: If this branch is bound, only remove the revisions from the
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local branch. If this branch is not bound, it is an error to pass
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:param keep_tags: Whether to keep tags pointing at the removed revisions
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unlockable.append(tree)
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unlockable.append(branch)
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pending_merges = tree.get_parent_ids()[1:]
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if branch.get_bound_location() is None:
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raise errors.LocalRequiresBoundBranch()
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master = branch.get_master_branch()
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if master is not None:
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unlockable.append(master)
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old_revno, old_tip = branch.last_revision_info()
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if master is not None and old_tip != master.last_revision():
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raise BoundBranchOutOfDate(branch, master)
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new_revision_id = old_tip
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graph = branch.repository.get_graph()
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for rev_id in graph.iter_lefthand_ancestry(old_tip):
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if cur_revno == new_revno:
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new_revision_id = rev_id
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print 'Removing revno %d: %s' % (cur_revno, rev_id)
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parents = graph.get_parent_map([rev_id]).get(rev_id, None)
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# When we finish popping off the pending merges, we want
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# them to stay in the order that they used to be.
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# but we pop from the end, so reverse the order, and
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# then get the order right at the end
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pending_merges.extend(reversed(parents[1:]))
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# We ran off the end of revisions, which means we should be trying
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# to get to NULL_REVISION
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new_revision_id = _mod_revision.NULL_REVISION
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if master is not None:
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master.set_last_revision_info(new_revno, new_revision_id)
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branch.set_last_revision_info(new_revno, new_revision_id)
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for hook in Branch.hooks['post_uncommit']:
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hook_new_tip = new_revision_id
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if hook_new_tip == _mod_revision.NULL_REVISION:
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hook(hook_local, hook_master, old_revno, old_tip, new_revno,
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if branch.supports_tags() and not keep_tags:
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remove_tags(branch, graph, old_tip, new_revision_id)
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if not _mod_revision.is_null(new_revision_id):
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parents = [new_revision_id]
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parents.extend(reversed(pending_merges))
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tree.set_parent_ids(parents)
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for item in reversed(unlockable):