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# Copyright (C) 2006 Canonical Ltd
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# Copyright (C) 2006-2010 Canonical Ltd
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# clients that don't anticipate errors from this method.
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default_format = BzrDirFormat.get_default_format()
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real_bzrdir = default_format.open(t, _found=True)
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bzr_prober = BzrProber()
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real_bzrdir._format.probe_transport(t)
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bzr_prober.probe_transport(t)
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except (errors.NotBranchError, errors.UnknownFormatError):
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return SuccessfulSmartServerResponse((answer,))
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class SmartServerRequestOpenBzrDir_2_1(SmartServerRequest):
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"""Is there a BzrDir present, and if so does it have a working tree?
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t = self.transport_from_client_path(path)
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except errors.PathNotChild:
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# The client is trying to ask about a path that they have no access
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return SuccessfulSmartServerResponse(('no',))
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bd = BzrDir.open_from_transport(t)
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except errors.NotBranchError:
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if bd.has_workingtree():
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return SuccessfulSmartServerResponse(answer)
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class SmartServerRequestBzrDir(SmartServerRequest):
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def do(self, path, *args):
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self._bzrdir = BzrDir.open_from_transport(
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self.transport_from_client_path(path))
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except errors.NotBranchError:
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return FailedSmartServerResponse(('nobranch', ))
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except errors.NotBranchError, e:
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return FailedSmartServerResponse(('nobranch',))
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return self.do_bzrdir_request(*args)
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def _boolean_to_yes_no(self, a_boolean):
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"""Get the relative path for repository from current_transport."""
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# the relpath of the bzrdir in the found repository gives us the
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# path segments to pop-out.
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relpath = repository.bzrdir.root_transport.relpath(
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relpath = repository.user_transport.relpath(
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current_transport.base)
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segments = ['..'] * len(relpath.split('/'))
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:param path: The path to the bzrdir.
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:param network_name: The network name of the branch type to create.
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:return: (ok, network_name)
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:return: ('ok', branch_format, repo_path, rich_root, tree_ref,
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external_lookup, repo_format)
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bzrdir = BzrDir.open_from_transport(
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self.transport_from_client_path(path))
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# It is returned locked, but we need to do the lock to get the lock
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repo_lock_token = repo.lock_write() or ''
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repo_lock_token = repo.lock_write().repository_token or ''
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if repo_lock_token:
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repo.leave_lock_in_place()
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return SuccessfulSmartServerResponse(('ok', ''))
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return SuccessfulSmartServerResponse(('ok', reference_url))
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except errors.NotBranchError:
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return FailedSmartServerResponse(('nobranch', ))
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except errors.NotBranchError, e:
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return FailedSmartServerResponse(('nobranch',))
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class SmartServerRequestOpenBranchV2(SmartServerRequestBzrDir):
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return SuccessfulSmartServerResponse(('branch', format))
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return SuccessfulSmartServerResponse(('ref', reference_url))
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except errors.NotBranchError:
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return FailedSmartServerResponse(('nobranch', ))
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except errors.NotBranchError, e:
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return FailedSmartServerResponse(('nobranch',))
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class SmartServerRequestOpenBranchV3(SmartServerRequestBzrDir):
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def do_bzrdir_request(self):
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"""Open a branch at path and return the reference or format.
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This version introduced in 2.1.
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Differences to SmartServerRequestOpenBranchV2:
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* can return 2-element ('nobranch', extra), where 'extra' is a string
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with an explanation like 'location is a repository'. Previously
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a 'nobranch' response would never have more than one element.
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reference_url = self._bzrdir.get_branch_reference()
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if reference_url is None:
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br = self._bzrdir.open_branch(ignore_fallbacks=True)
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format = br._format.network_name()
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return SuccessfulSmartServerResponse(('branch', format))
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return SuccessfulSmartServerResponse(('ref', reference_url))
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except errors.NotBranchError, e:
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# Stringify the exception so that its .detail attribute will be
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if detail.startswith(': '):
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return FailedSmartServerResponse(resp)