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# Copyright (C) 2007 Canonical Ltd
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
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from bzrlib.symbol_versioning import deprecated_function, deprecated_in
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STEP_UNIQUE_SEARCHER_EVERY = 5
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# DIAGRAM of terminology
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# In this diagram, relative to G and H:
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# A, B, C, D, E are common ancestors.
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# C, D and E are border ancestors, because each has a non-common descendant.
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# D and E are least common ancestors because none of their descendants are
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# C is not a least common ancestor because its descendant, E, is a common
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# The find_unique_lca algorithm will pick A in two steps:
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# 1. find_lca('G', 'H') => ['D', 'E']
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# 2. Since len(['D', 'E']) > 1, find_lca('D', 'E') => ['A']
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class DictParentsProvider(object):
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"""A parents provider for Graph objects."""
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def __init__(self, ancestry):
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self.ancestry = ancestry
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return 'DictParentsProvider(%r)' % self.ancestry
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def get_parent_map(self, keys):
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"""See StackedParentsProvider.get_parent_map"""
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ancestry = self.ancestry
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return dict((k, ancestry[k]) for k in keys if k in ancestry)
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@deprecated_function(deprecated_in((1, 16, 0)))
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def _StackedParentsProvider(*args, **kwargs):
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return StackedParentsProvider(*args, **kwargs)
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class StackedParentsProvider(object):
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"""A parents provider which stacks (or unions) multiple providers.
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The providers are queries in the order of the provided parent_providers.
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def __init__(self, parent_providers):
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self._parent_providers = parent_providers
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return "%s(%r)" % (self.__class__.__name__, self._parent_providers)
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def get_parent_map(self, keys):
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"""Get a mapping of keys => parents
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A dictionary is returned with an entry for each key present in this
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source. If this source doesn't have information about a key, it should
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[NULL_REVISION] is used as the parent of the first user-committed
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revision. Its parent list is empty.
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:param keys: An iterable returning keys to check (eg revision_ids)
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:return: A dictionary mapping each key to its parents
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for parents_provider in self._parent_providers:
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new_found = parents_provider.get_parent_map(remaining)
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found.update(new_found)
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remaining.difference_update(new_found)
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class CachingParentsProvider(object):
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"""A parents provider which will cache the revision => parents as a dict.
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This is useful for providers which have an expensive look up.
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Either a ParentsProvider or a get_parent_map-like callback may be
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supplied. If it provides extra un-asked-for parents, they will be cached,
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but filtered out of get_parent_map.
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The cache is enabled by default, but may be disabled and re-enabled.
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def __init__(self, parent_provider=None, get_parent_map=None):
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:param parent_provider: The ParentProvider to use. It or
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get_parent_map must be supplied.
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:param get_parent_map: The get_parent_map callback to use. It or
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parent_provider must be supplied.
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self._real_provider = parent_provider
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if get_parent_map is None:
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self._get_parent_map = self._real_provider.get_parent_map
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self._get_parent_map = get_parent_map
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self.enable_cache(True)
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return "%s(%r)" % (self.__class__.__name__, self._real_provider)
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def enable_cache(self, cache_misses=True):
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if self._cache is not None:
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raise AssertionError('Cache enabled when already enabled.')
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self._cache_misses = cache_misses
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self.missing_keys = set()
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def disable_cache(self):
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"""Disable and clear the cache."""
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self._cache_misses = None
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self.missing_keys = set()
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def get_cached_map(self):
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"""Return any cached get_parent_map values."""
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if self._cache is None:
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return dict(self._cache)
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def get_parent_map(self, keys):
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"""See StackedParentsProvider.get_parent_map."""
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cache = self._get_parent_map(keys)
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needed_revisions = set(key for key in keys if key not in cache)
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# Do not ask for negatively cached keys
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needed_revisions.difference_update(self.missing_keys)
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parent_map = self._get_parent_map(needed_revisions)
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cache.update(parent_map)
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if self._cache_misses:
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for key in needed_revisions:
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if key not in parent_map:
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self.note_missing_key(key)
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value = cache.get(key)
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if value is not None:
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def note_missing_key(self, key):
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"""Note that key is a missing key."""
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if self._cache_misses:
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self.missing_keys.add(key)
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"""Provide incremental access to revision graphs.
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This is the generic implementation; it is intended to be subclassed to
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specialize it for other repository types.
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def __init__(self, parents_provider):
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"""Construct a Graph that uses several graphs as its input
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This should not normally be invoked directly, because there may be
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specialized implementations for particular repository types. See
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Repository.get_graph().
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:param parents_provider: An object providing a get_parent_map call
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conforming to the behavior of
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StackedParentsProvider.get_parent_map.
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if getattr(parents_provider, 'get_parents', None) is not None:
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self.get_parents = parents_provider.get_parents
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if getattr(parents_provider, 'get_parent_map', None) is not None:
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self.get_parent_map = parents_provider.get_parent_map
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self._parents_provider = parents_provider
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return 'Graph(%r)' % self._parents_provider
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def find_lca(self, *revisions):
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"""Determine the lowest common ancestors of the provided revisions
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A lowest common ancestor is a common ancestor none of whose
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descendants are common ancestors. In graphs, unlike trees, there may
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be multiple lowest common ancestors.
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This algorithm has two phases. Phase 1 identifies border ancestors,
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and phase 2 filters border ancestors to determine lowest common
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In phase 1, border ancestors are identified, using a breadth-first
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search starting at the bottom of the graph. Searches are stopped
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whenever a node or one of its descendants is determined to be common
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In phase 2, the border ancestors are filtered to find the least
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common ancestors. This is done by searching the ancestries of each
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Phase 2 is perfomed on the principle that a border ancestor that is
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not an ancestor of any other border ancestor is a least common
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Searches are stopped when they find a node that is determined to be a
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common ancestor of all border ancestors, because this shows that it
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cannot be a descendant of any border ancestor.
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The scaling of this operation should be proportional to
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1. The number of uncommon ancestors
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2. The number of border ancestors
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3. The length of the shortest path between a border ancestor and an
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ancestor of all border ancestors.
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border_common, common, sides = self._find_border_ancestors(revisions)
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# We may have common ancestors that can be reached from each other.
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# - ask for the heads of them to filter it down to only ones that
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# cannot be reached from each other - phase 2.
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return self.heads(border_common)
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def find_difference(self, left_revision, right_revision):
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"""Determine the graph difference between two revisions"""
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border, common, searchers = self._find_border_ancestors(
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[left_revision, right_revision])
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self._search_for_extra_common(common, searchers)
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left = searchers[0].seen
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right = searchers[1].seen
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return (left.difference(right), right.difference(left))
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def find_distance_to_null(self, target_revision_id, known_revision_ids):
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"""Find the left-hand distance to the NULL_REVISION.
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(This can also be considered the revno of a branch at
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:param target_revision_id: A revision_id which we would like to know
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:param known_revision_ids: [(revision_id, revno)] A list of known
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revno, revision_id tuples. We'll use this to seed the search.
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# Map from revision_ids to a known value for their revno
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known_revnos = dict(known_revision_ids)
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cur_tip = target_revision_id
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NULL_REVISION = revision.NULL_REVISION
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known_revnos[NULL_REVISION] = 0
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searching_known_tips = list(known_revnos.keys())
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unknown_searched = {}
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while cur_tip not in known_revnos:
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unknown_searched[cur_tip] = num_steps
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to_search = set([cur_tip])
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to_search.update(searching_known_tips)
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parent_map = self.get_parent_map(to_search)
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parents = parent_map.get(cur_tip, None)
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if not parents: # An empty list or None is a ghost
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raise errors.GhostRevisionsHaveNoRevno(target_revision_id,
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for revision_id in searching_known_tips:
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parents = parent_map.get(revision_id, None)
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next_revno = known_revnos[revision_id] - 1
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if next in unknown_searched:
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# We have enough information to return a value right now
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return next_revno + unknown_searched[next]
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if next in known_revnos:
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known_revnos[next] = next_revno
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next_known_tips.append(next)
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searching_known_tips = next_known_tips
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# We reached a known revision, so just add in how many steps it took to
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return known_revnos[cur_tip] + num_steps
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def find_unique_ancestors(self, unique_revision, common_revisions):
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"""Find the unique ancestors for a revision versus others.
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This returns the ancestry of unique_revision, excluding all revisions
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in the ancestry of common_revisions. If unique_revision is in the
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ancestry, then the empty set will be returned.
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:param unique_revision: The revision_id whose ancestry we are
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XXX: Would this API be better if we allowed multiple revisions on
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:param common_revisions: Revision_ids of ancestries to exclude.
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:return: A set of revisions in the ancestry of unique_revision
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if unique_revision in common_revisions:
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# Algorithm description
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# 1) Walk backwards from the unique node and all common nodes.
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# 2) When a node is seen by both sides, stop searching it in the unique
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# walker, include it in the common walker.
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# 3) Stop searching when there are no nodes left for the unique walker.
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# At this point, you have a maximal set of unique nodes. Some of
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# them may actually be common, and you haven't reached them yet.
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# 4) Start new searchers for the unique nodes, seeded with the
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# information you have so far.
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# 5) Continue searching, stopping the common searches when the search
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# tip is an ancestor of all unique nodes.
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# 6) Aggregate together unique searchers when they are searching the
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# same tips. When all unique searchers are searching the same node,
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# stop move it to a single 'all_unique_searcher'.
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# 7) The 'all_unique_searcher' represents the very 'tip' of searching.
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# Most of the time this produces very little important information.
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# So don't step it as quickly as the other searchers.
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# 8) Search is done when all common searchers have completed.
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unique_searcher, common_searcher = self._find_initial_unique_nodes(
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[unique_revision], common_revisions)
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unique_nodes = unique_searcher.seen.difference(common_searcher.seen)
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(all_unique_searcher,
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unique_tip_searchers) = self._make_unique_searchers(unique_nodes,
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unique_searcher, common_searcher)
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self._refine_unique_nodes(unique_searcher, all_unique_searcher,
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unique_tip_searchers, common_searcher)
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true_unique_nodes = unique_nodes.difference(common_searcher.seen)
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if 'graph' in debug.debug_flags:
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trace.mutter('Found %d truly unique nodes out of %d',
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len(true_unique_nodes), len(unique_nodes))
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return true_unique_nodes
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def _find_initial_unique_nodes(self, unique_revisions, common_revisions):
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"""Steps 1-3 of find_unique_ancestors.
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Find the maximal set of unique nodes. Some of these might actually
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still be common, but we are sure that there are no other unique nodes.
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:return: (unique_searcher, common_searcher)
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unique_searcher = self._make_breadth_first_searcher(unique_revisions)
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# we know that unique_revisions aren't in common_revisions, so skip
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unique_searcher.next()
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common_searcher = self._make_breadth_first_searcher(common_revisions)
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# As long as we are still finding unique nodes, keep searching
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while unique_searcher._next_query:
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next_unique_nodes = set(unique_searcher.step())
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next_common_nodes = set(common_searcher.step())
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# Check if either searcher encounters new nodes seen by the other
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unique_are_common_nodes = next_unique_nodes.intersection(
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common_searcher.seen)
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unique_are_common_nodes.update(
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next_common_nodes.intersection(unique_searcher.seen))
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if unique_are_common_nodes:
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ancestors = unique_searcher.find_seen_ancestors(
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unique_are_common_nodes)
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# TODO: This is a bit overboard, we only really care about
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# the ancestors of the tips because the rest we
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# already know. This is *correct* but causes us to
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# search too much ancestry.
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ancestors.update(common_searcher.find_seen_ancestors(ancestors))
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unique_searcher.stop_searching_any(ancestors)
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common_searcher.start_searching(ancestors)
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return unique_searcher, common_searcher
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def _make_unique_searchers(self, unique_nodes, unique_searcher,
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"""Create a searcher for all the unique search tips (step 4).
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As a side effect, the common_searcher will stop searching any nodes
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that are ancestors of the unique searcher tips.
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:return: (all_unique_searcher, unique_tip_searchers)
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unique_tips = self._remove_simple_descendants(unique_nodes,
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self.get_parent_map(unique_nodes))
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if len(unique_tips) == 1:
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unique_tip_searchers = []
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ancestor_all_unique = unique_searcher.find_seen_ancestors(unique_tips)
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unique_tip_searchers = []
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for tip in unique_tips:
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revs_to_search = unique_searcher.find_seen_ancestors([tip])
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revs_to_search.update(
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common_searcher.find_seen_ancestors(revs_to_search))
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searcher = self._make_breadth_first_searcher(revs_to_search)
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# We don't care about the starting nodes.
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searcher._label = tip
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unique_tip_searchers.append(searcher)
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ancestor_all_unique = None
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for searcher in unique_tip_searchers:
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if ancestor_all_unique is None:
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ancestor_all_unique = set(searcher.seen)
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ancestor_all_unique = ancestor_all_unique.intersection(
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# Collapse all the common nodes into a single searcher
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all_unique_searcher = self._make_breadth_first_searcher(
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if ancestor_all_unique:
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# We've seen these nodes in all the searchers, so we'll just go to
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all_unique_searcher.step()
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# Stop any search tips that are already known as ancestors of the
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stopped_common = common_searcher.stop_searching_any(
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common_searcher.find_seen_ancestors(ancestor_all_unique))
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for searcher in unique_tip_searchers:
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total_stopped += len(searcher.stop_searching_any(
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searcher.find_seen_ancestors(ancestor_all_unique)))
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if 'graph' in debug.debug_flags:
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trace.mutter('For %d unique nodes, created %d + 1 unique searchers'
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' (%d stopped search tips, %d common ancestors'
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' (%d stopped common)',
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len(unique_nodes), len(unique_tip_searchers),
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total_stopped, len(ancestor_all_unique),
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return all_unique_searcher, unique_tip_searchers
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def _step_unique_and_common_searchers(self, common_searcher,
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unique_tip_searchers,
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"""Step all the searchers"""
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newly_seen_common = set(common_searcher.step())
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newly_seen_unique = set()
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for searcher in unique_tip_searchers:
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next = set(searcher.step())
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next.update(unique_searcher.find_seen_ancestors(next))
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next.update(common_searcher.find_seen_ancestors(next))
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for alt_searcher in unique_tip_searchers:
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if alt_searcher is searcher:
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next.update(alt_searcher.find_seen_ancestors(next))
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searcher.start_searching(next)
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newly_seen_unique.update(next)
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return newly_seen_common, newly_seen_unique
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def _find_nodes_common_to_all_unique(self, unique_tip_searchers,
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newly_seen_unique, step_all_unique):
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"""Find nodes that are common to all unique_tip_searchers.
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If it is time, step the all_unique_searcher, and add its nodes to the
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common_to_all_unique_nodes = newly_seen_unique.copy()
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for searcher in unique_tip_searchers:
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common_to_all_unique_nodes.intersection_update(searcher.seen)
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common_to_all_unique_nodes.intersection_update(
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all_unique_searcher.seen)
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# Step all-unique less frequently than the other searchers.
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# In the common case, we don't need to spider out far here, so
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# avoid doing extra work.
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tstart = time.clock()
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nodes = all_unique_searcher.step()
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common_to_all_unique_nodes.update(nodes)
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if 'graph' in debug.debug_flags:
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tdelta = time.clock() - tstart
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trace.mutter('all_unique_searcher step() took %.3fs'
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'for %d nodes (%d total), iteration: %s',
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tdelta, len(nodes), len(all_unique_searcher.seen),
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all_unique_searcher._iterations)
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return common_to_all_unique_nodes
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def _collapse_unique_searchers(self, unique_tip_searchers,
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common_to_all_unique_nodes):
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"""Combine searchers that are searching the same tips.
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When two searchers are searching the same tips, we can stop one of the
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searchers. We also know that the maximal set of common ancestors is the
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intersection of the two original searchers.
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:return: A list of searchers that are searching unique nodes.
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# Filter out searchers that don't actually search different
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# nodes. We already have the ancestry intersection for them
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unique_search_tips = {}
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for searcher in unique_tip_searchers:
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stopped = searcher.stop_searching_any(common_to_all_unique_nodes)
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will_search_set = frozenset(searcher._next_query)
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if not will_search_set:
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if 'graph' in debug.debug_flags:
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trace.mutter('Unique searcher %s was stopped.'
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' (%s iterations) %d nodes stopped',
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searcher._iterations,
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elif will_search_set not in unique_search_tips:
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# This searcher is searching a unique set of nodes, let it
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unique_search_tips[will_search_set] = [searcher]
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unique_search_tips[will_search_set].append(searcher)
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# TODO: it might be possible to collapse searchers faster when they
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# only have *some* search tips in common.
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next_unique_searchers = []
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for searchers in unique_search_tips.itervalues():
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if len(searchers) == 1:
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# Searching unique tips, go for it
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next_unique_searchers.append(searchers[0])
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# These searchers have started searching the same tips, we
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# don't need them to cover the same ground. The
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# intersection of their ancestry won't change, so create a
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# new searcher, combining their histories.
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next_searcher = searchers[0]
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for searcher in searchers[1:]:
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next_searcher.seen.intersection_update(searcher.seen)
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if 'graph' in debug.debug_flags:
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trace.mutter('Combining %d searchers into a single'
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' searcher searching %d nodes with'
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len(next_searcher._next_query),
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len(next_searcher.seen))
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next_unique_searchers.append(next_searcher)
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return next_unique_searchers
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def _refine_unique_nodes(self, unique_searcher, all_unique_searcher,
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unique_tip_searchers, common_searcher):
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"""Steps 5-8 of find_unique_ancestors.
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This function returns when common_searcher has stopped searching for
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# We step the ancestor_all_unique searcher only every
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# STEP_UNIQUE_SEARCHER_EVERY steps.
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step_all_unique_counter = 0
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# While we still have common nodes to search
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while common_searcher._next_query:
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newly_seen_unique) = self._step_unique_and_common_searchers(
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common_searcher, unique_tip_searchers, unique_searcher)
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# These nodes are common ancestors of all unique nodes
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common_to_all_unique_nodes = self._find_nodes_common_to_all_unique(
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unique_tip_searchers, all_unique_searcher, newly_seen_unique,
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step_all_unique_counter==0)
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step_all_unique_counter = ((step_all_unique_counter + 1)
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% STEP_UNIQUE_SEARCHER_EVERY)
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if newly_seen_common:
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# If a 'common' node is an ancestor of all unique searchers, we
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# can stop searching it.
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common_searcher.stop_searching_any(
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all_unique_searcher.seen.intersection(newly_seen_common))
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if common_to_all_unique_nodes:
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common_to_all_unique_nodes.update(
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common_searcher.find_seen_ancestors(
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common_to_all_unique_nodes))
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# The all_unique searcher can start searching the common nodes
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# but everyone else can stop.
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# This is the sort of thing where we would like to not have it
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# start_searching all of the nodes, but only mark all of them
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# as seen, and have it search only the actual tips. Otherwise
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# it is another get_parent_map() traversal for it to figure out
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# what we already should know.
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all_unique_searcher.start_searching(common_to_all_unique_nodes)
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common_searcher.stop_searching_any(common_to_all_unique_nodes)
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next_unique_searchers = self._collapse_unique_searchers(
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unique_tip_searchers, common_to_all_unique_nodes)
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if len(unique_tip_searchers) != len(next_unique_searchers):
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if 'graph' in debug.debug_flags:
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trace.mutter('Collapsed %d unique searchers => %d'
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len(unique_tip_searchers),
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len(next_unique_searchers),
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all_unique_searcher._iterations)
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unique_tip_searchers = next_unique_searchers
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def get_parent_map(self, revisions):
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"""Get a map of key:parent_list for revisions.
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This implementation delegates to get_parents, for old parent_providers
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that do not supply get_parent_map.
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for rev, parents in self.get_parents(revisions):
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if parents is not None:
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result[rev] = parents
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def _make_breadth_first_searcher(self, revisions):
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return _BreadthFirstSearcher(revisions, self)
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def _find_border_ancestors(self, revisions):
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"""Find common ancestors with at least one uncommon descendant.
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Border ancestors are identified using a breadth-first
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search starting at the bottom of the graph. Searches are stopped
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whenever a node or one of its descendants is determined to be common.
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This will scale with the number of uncommon ancestors.
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As well as the border ancestors, a set of seen common ancestors and a
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list of sets of seen ancestors for each input revision is returned.
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This allows calculation of graph difference from the results of this
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if None in revisions:
649
raise errors.InvalidRevisionId(None, self)
650
common_ancestors = set()
651
searchers = [self._make_breadth_first_searcher([r])
653
active_searchers = searchers[:]
654
border_ancestors = set()
658
for searcher in searchers:
659
new_ancestors = searcher.step()
661
newly_seen.update(new_ancestors)
663
for revision in newly_seen:
664
if revision in common_ancestors:
665
# Not a border ancestor because it was seen as common
667
new_common.add(revision)
669
for searcher in searchers:
670
if revision not in searcher.seen:
673
# This is a border because it is a first common that we see
674
# after walking for a while.
675
border_ancestors.add(revision)
676
new_common.add(revision)
678
for searcher in searchers:
679
new_common.update(searcher.find_seen_ancestors(new_common))
680
for searcher in searchers:
681
searcher.start_searching(new_common)
682
common_ancestors.update(new_common)
684
# Figure out what the searchers will be searching next, and if
685
# there is only 1 set being searched, then we are done searching,
686
# since all searchers would have to be searching the same data,
687
# thus it *must* be in common.
688
unique_search_sets = set()
689
for searcher in searchers:
690
will_search_set = frozenset(searcher._next_query)
691
if will_search_set not in unique_search_sets:
692
# This searcher is searching a unique set of nodes, let it
693
unique_search_sets.add(will_search_set)
695
if len(unique_search_sets) == 1:
696
nodes = unique_search_sets.pop()
697
uncommon_nodes = nodes.difference(common_ancestors)
699
raise AssertionError("Somehow we ended up converging"
700
" without actually marking them as"
703
"\nuncommon_nodes: %s"
704
% (revisions, uncommon_nodes))
706
return border_ancestors, common_ancestors, searchers
708
def heads(self, keys):
709
"""Return the heads from amongst keys.
711
This is done by searching the ancestries of each key. Any key that is
712
reachable from another key is not returned; all the others are.
714
This operation scales with the relative depth between any two keys. If
715
any two keys are completely disconnected all ancestry of both sides
718
:param keys: An iterable of keys.
719
:return: A set of the heads. Note that as a set there is no ordering
720
information. Callers will need to filter their input to create
721
order if they need it.
723
candidate_heads = set(keys)
724
if revision.NULL_REVISION in candidate_heads:
725
# NULL_REVISION is only a head if it is the only entry
726
candidate_heads.remove(revision.NULL_REVISION)
727
if not candidate_heads:
728
return set([revision.NULL_REVISION])
729
if len(candidate_heads) < 2:
730
return candidate_heads
731
searchers = dict((c, self._make_breadth_first_searcher([c]))
732
for c in candidate_heads)
733
active_searchers = dict(searchers)
734
# skip over the actual candidate for each searcher
735
for searcher in active_searchers.itervalues():
737
# The common walker finds nodes that are common to two or more of the
738
# input keys, so that we don't access all history when a currently
739
# uncommon search point actually meets up with something behind a
740
# common search point. Common search points do not keep searches
741
# active; they just allow us to make searches inactive without
742
# accessing all history.
743
common_walker = self._make_breadth_first_searcher([])
744
while len(active_searchers) > 0:
749
except StopIteration:
750
# No common points being searched at this time.
752
for candidate in active_searchers.keys():
754
searcher = active_searchers[candidate]
756
# rare case: we deleted candidate in a previous iteration
757
# through this for loop, because it was determined to be
758
# a descendant of another candidate.
761
ancestors.update(searcher.next())
762
except StopIteration:
763
del active_searchers[candidate]
765
# process found nodes
767
for ancestor in ancestors:
768
if ancestor in candidate_heads:
769
candidate_heads.remove(ancestor)
770
del searchers[ancestor]
771
if ancestor in active_searchers:
772
del active_searchers[ancestor]
773
# it may meet up with a known common node
774
if ancestor in common_walker.seen:
775
# some searcher has encountered our known common nodes:
777
ancestor_set = set([ancestor])
778
for searcher in searchers.itervalues():
779
searcher.stop_searching_any(ancestor_set)
781
# or it may have been just reached by all the searchers:
782
for searcher in searchers.itervalues():
783
if ancestor not in searcher.seen:
786
# The final active searcher has just reached this node,
787
# making it be known as a descendant of all candidates,
788
# so we can stop searching it, and any seen ancestors
789
new_common.add(ancestor)
790
for searcher in searchers.itervalues():
792
searcher.find_seen_ancestors([ancestor])
793
searcher.stop_searching_any(seen_ancestors)
794
common_walker.start_searching(new_common)
795
return candidate_heads
797
def find_merge_order(self, tip_revision_id, lca_revision_ids):
798
"""Find the order that each revision was merged into tip.
800
This basically just walks backwards with a stack, and walks left-first
801
until it finds a node to stop.
803
if len(lca_revision_ids) == 1:
804
return list(lca_revision_ids)
805
looking_for = set(lca_revision_ids)
806
# TODO: Is there a way we could do this "faster" by batching up the
807
# get_parent_map requests?
808
# TODO: Should we also be culling the ancestry search right away? We
809
# could add looking_for to the "stop" list, and walk their
810
# ancestry in batched mode. The flip side is it might mean we walk a
811
# lot of "stop" nodes, rather than only the minimum.
812
# Then again, without it we may trace back into ancestry we could have
814
stack = [tip_revision_id]
817
while stack and looking_for:
820
if next in looking_for:
822
looking_for.remove(next)
823
if len(looking_for) == 1:
824
found.append(looking_for.pop())
827
parent_ids = self.get_parent_map([next]).get(next, None)
828
if not parent_ids: # Ghost, nothing to search here
830
for parent_id in reversed(parent_ids):
831
# TODO: (performance) We see the parent at this point, but we
832
# wait to mark it until later to make sure we get left
833
# parents before right parents. However, instead of
834
# waiting until we have traversed enough parents, we
835
# could instead note that we've found it, and once all
836
# parents are in the stack, just reverse iterate the
838
if parent_id not in stop:
839
# this will need to be searched
840
stack.append(parent_id)
844
def find_unique_lca(self, left_revision, right_revision,
846
"""Find a unique LCA.
848
Find lowest common ancestors. If there is no unique common
849
ancestor, find the lowest common ancestors of those ancestors.
851
Iteration stops when a unique lowest common ancestor is found.
852
The graph origin is necessarily a unique lowest common ancestor.
854
Note that None is not an acceptable substitute for NULL_REVISION.
855
in the input for this method.
857
:param count_steps: If True, the return value will be a tuple of
858
(unique_lca, steps) where steps is the number of times that
859
find_lca was run. If False, only unique_lca is returned.
861
revisions = [left_revision, right_revision]
865
lca = self.find_lca(*revisions)
873
raise errors.NoCommonAncestor(left_revision, right_revision)
876
def iter_ancestry(self, revision_ids):
877
"""Iterate the ancestry of this revision.
879
:param revision_ids: Nodes to start the search
880
:return: Yield tuples mapping a revision_id to its parents for the
881
ancestry of revision_id.
882
Ghosts will be returned with None as their parents, and nodes
883
with no parents will have NULL_REVISION as their only parent. (As
884
defined by get_parent_map.)
885
There will also be a node for (NULL_REVISION, ())
887
pending = set(revision_ids)
890
processed.update(pending)
891
next_map = self.get_parent_map(pending)
893
for item in next_map.iteritems():
895
next_pending.update(p for p in item[1] if p not in processed)
896
ghosts = pending.difference(next_map)
899
pending = next_pending
901
def iter_topo_order(self, revisions):
902
"""Iterate through the input revisions in topological order.
904
This sorting only ensures that parents come before their children.
905
An ancestor may sort after a descendant if the relationship is not
906
visible in the supplied list of revisions.
908
sorter = tsort.TopoSorter(self.get_parent_map(revisions))
909
return sorter.iter_topo_order()
911
def is_ancestor(self, candidate_ancestor, candidate_descendant):
912
"""Determine whether a revision is an ancestor of another.
914
We answer this using heads() as heads() has the logic to perform the
915
smallest number of parent lookups to determine the ancestral
916
relationship between N revisions.
918
return set([candidate_descendant]) == self.heads(
919
[candidate_ancestor, candidate_descendant])
921
def is_between(self, revid, lower_bound_revid, upper_bound_revid):
922
"""Determine whether a revision is between two others.
924
returns true if and only if:
925
lower_bound_revid <= revid <= upper_bound_revid
927
return ((upper_bound_revid is None or
928
self.is_ancestor(revid, upper_bound_revid)) and
929
(lower_bound_revid is None or
930
self.is_ancestor(lower_bound_revid, revid)))
932
def _search_for_extra_common(self, common, searchers):
933
"""Make sure that unique nodes are genuinely unique.
935
After _find_border_ancestors, all nodes marked "common" are indeed
936
common. Some of the nodes considered unique are not, due to history
937
shortcuts stopping the searches early.
939
We know that we have searched enough when all common search tips are
940
descended from all unique (uncommon) nodes because we know that a node
941
cannot be an ancestor of its own ancestor.
943
:param common: A set of common nodes
944
:param searchers: The searchers returned from _find_border_ancestors
948
# A) The passed in searchers should all be on the same tips, thus
949
# they should be considered the "common" searchers.
950
# B) We find the difference between the searchers, these are the
951
# "unique" nodes for each side.
952
# C) We do a quick culling so that we only start searching from the
953
# more interesting unique nodes. (A unique ancestor is more
954
# interesting than any of its children.)
955
# D) We start searching for ancestors common to all unique nodes.
956
# E) We have the common searchers stop searching any ancestors of
958
# F) When there are no more common search tips, we stop
960
# TODO: We need a way to remove unique_searchers when they overlap with
961
# other unique searchers.
962
if len(searchers) != 2:
963
raise NotImplementedError(
964
"Algorithm not yet implemented for > 2 searchers")
965
common_searchers = searchers
966
left_searcher = searchers[0]
967
right_searcher = searchers[1]
968
unique = left_searcher.seen.symmetric_difference(right_searcher.seen)
969
if not unique: # No unique nodes, nothing to do
971
total_unique = len(unique)
972
unique = self._remove_simple_descendants(unique,
973
self.get_parent_map(unique))
974
simple_unique = len(unique)
976
unique_searchers = []
977
for revision_id in unique:
978
if revision_id in left_searcher.seen:
979
parent_searcher = left_searcher
981
parent_searcher = right_searcher
982
revs_to_search = parent_searcher.find_seen_ancestors([revision_id])
983
if not revs_to_search: # XXX: This shouldn't be possible
984
revs_to_search = [revision_id]
985
searcher = self._make_breadth_first_searcher(revs_to_search)
986
# We don't care about the starting nodes.
988
unique_searchers.append(searcher)
990
# possible todo: aggregate the common searchers into a single common
991
# searcher, just make sure that we include the nodes into the .seen
992
# properties of the original searchers
994
ancestor_all_unique = None
995
for searcher in unique_searchers:
996
if ancestor_all_unique is None:
997
ancestor_all_unique = set(searcher.seen)
999
ancestor_all_unique = ancestor_all_unique.intersection(
1002
trace.mutter('Started %s unique searchers for %s unique revisions',
1003
simple_unique, total_unique)
1005
while True: # If we have no more nodes we have nothing to do
1006
newly_seen_common = set()
1007
for searcher in common_searchers:
1008
newly_seen_common.update(searcher.step())
1009
newly_seen_unique = set()
1010
for searcher in unique_searchers:
1011
newly_seen_unique.update(searcher.step())
1012
new_common_unique = set()
1013
for revision in newly_seen_unique:
1014
for searcher in unique_searchers:
1015
if revision not in searcher.seen:
1018
# This is a border because it is a first common that we see
1019
# after walking for a while.
1020
new_common_unique.add(revision)
1021
if newly_seen_common:
1022
# These are nodes descended from one of the 'common' searchers.
1023
# Make sure all searchers are on the same page
1024
for searcher in common_searchers:
1025
newly_seen_common.update(
1026
searcher.find_seen_ancestors(newly_seen_common))
1027
# We start searching the whole ancestry. It is a bit wasteful,
1028
# though. We really just want to mark all of these nodes as
1029
# 'seen' and then start just the tips. However, it requires a
1030
# get_parent_map() call to figure out the tips anyway, and all
1031
# redundant requests should be fairly fast.
1032
for searcher in common_searchers:
1033
searcher.start_searching(newly_seen_common)
1035
# If a 'common' node is an ancestor of all unique searchers, we
1036
# can stop searching it.
1037
stop_searching_common = ancestor_all_unique.intersection(
1039
if stop_searching_common:
1040
for searcher in common_searchers:
1041
searcher.stop_searching_any(stop_searching_common)
1042
if new_common_unique:
1043
# We found some ancestors that are common
1044
for searcher in unique_searchers:
1045
new_common_unique.update(
1046
searcher.find_seen_ancestors(new_common_unique))
1047
# Since these are common, we can grab another set of ancestors
1049
for searcher in common_searchers:
1050
new_common_unique.update(
1051
searcher.find_seen_ancestors(new_common_unique))
1053
# We can tell all of the unique searchers to start at these
1054
# nodes, and tell all of the common searchers to *stop*
1055
# searching these nodes
1056
for searcher in unique_searchers:
1057
searcher.start_searching(new_common_unique)
1058
for searcher in common_searchers:
1059
searcher.stop_searching_any(new_common_unique)
1060
ancestor_all_unique.update(new_common_unique)
1062
# Filter out searchers that don't actually search different
1063
# nodes. We already have the ancestry intersection for them
1064
next_unique_searchers = []
1065
unique_search_sets = set()
1066
for searcher in unique_searchers:
1067
will_search_set = frozenset(searcher._next_query)
1068
if will_search_set not in unique_search_sets:
1069
# This searcher is searching a unique set of nodes, let it
1070
unique_search_sets.add(will_search_set)
1071
next_unique_searchers.append(searcher)
1072
unique_searchers = next_unique_searchers
1073
for searcher in common_searchers:
1074
if searcher._next_query:
1077
# All common searcher have stopped searching
1080
def _remove_simple_descendants(self, revisions, parent_map):
1081
"""remove revisions which are children of other ones in the set
1083
This doesn't do any graph searching, it just checks the immediate
1084
parent_map to find if there are any children which can be removed.
1086
:param revisions: A set of revision_ids
1087
:return: A set of revision_ids with the children removed
1089
simple_ancestors = revisions.copy()
1090
# TODO: jam 20071214 we *could* restrict it to searching only the
1091
# parent_map of revisions already present in 'revisions', but
1092
# considering the general use case, I think this is actually
1095
# This is the same as the following loop. I don't know that it is any
1097
## simple_ancestors.difference_update(r for r, p_ids in parent_map.iteritems()
1098
## if p_ids is not None and revisions.intersection(p_ids))
1099
## return simple_ancestors
1101
# Yet Another Way, invert the parent map (which can be cached)
1103
## for revision_id, parent_ids in parent_map.iteritems():
1104
## for p_id in parent_ids:
1105
## descendants.setdefault(p_id, []).append(revision_id)
1106
## for revision in revisions.intersection(descendants):
1107
## simple_ancestors.difference_update(descendants[revision])
1108
## return simple_ancestors
1109
for revision, parent_ids in parent_map.iteritems():
1110
if parent_ids is None:
1112
for parent_id in parent_ids:
1113
if parent_id in revisions:
1114
# This node has a parent present in the set, so we can
1116
simple_ancestors.discard(revision)
1118
return simple_ancestors
1121
class HeadsCache(object):
1122
"""A cache of results for graph heads calls."""
1124
def __init__(self, graph):
1128
def heads(self, keys):
1129
"""Return the heads of keys.
1131
This matches the API of Graph.heads(), specifically the return value is
1132
a set which can be mutated, and ordering of the input is not preserved
1135
:see also: Graph.heads.
1136
:param keys: The keys to calculate heads for.
1137
:return: A set containing the heads, which may be mutated without
1138
affecting future lookups.
1140
keys = frozenset(keys)
1142
return set(self._heads[keys])
1144
heads = self.graph.heads(keys)
1145
self._heads[keys] = heads
1149
class FrozenHeadsCache(object):
1150
"""Cache heads() calls, assuming the caller won't modify them."""
1152
def __init__(self, graph):
1156
def heads(self, keys):
1157
"""Return the heads of keys.
1159
Similar to Graph.heads(). The main difference is that the return value
1160
is a frozen set which cannot be mutated.
1162
:see also: Graph.heads.
1163
:param keys: The keys to calculate heads for.
1164
:return: A frozenset containing the heads.
1166
keys = frozenset(keys)
1168
return self._heads[keys]
1170
heads = frozenset(self.graph.heads(keys))
1171
self._heads[keys] = heads
1174
def cache(self, keys, heads):
1175
"""Store a known value."""
1176
self._heads[frozenset(keys)] = frozenset(heads)
1179
class _BreadthFirstSearcher(object):
1180
"""Parallel search breadth-first the ancestry of revisions.
1182
This class implements the iterator protocol, but additionally
1183
1. provides a set of seen ancestors, and
1184
2. allows some ancestries to be unsearched, via stop_searching_any
1187
def __init__(self, revisions, parents_provider):
1188
self._iterations = 0
1189
self._next_query = set(revisions)
1191
self._started_keys = set(self._next_query)
1192
self._stopped_keys = set()
1193
self._parents_provider = parents_provider
1194
self._returning = 'next_with_ghosts'
1195
self._current_present = set()
1196
self._current_ghosts = set()
1197
self._current_parents = {}
1200
if self._iterations:
1201
prefix = "searching"
1204
search = '%s=%r' % (prefix, list(self._next_query))
1205
return ('_BreadthFirstSearcher(iterations=%d, %s,'
1206
' seen=%r)' % (self._iterations, search, list(self.seen)))
1208
def get_result(self):
1209
"""Get a SearchResult for the current state of this searcher.
1211
:return: A SearchResult for this search so far. The SearchResult is
1212
static - the search can be advanced and the search result will not
1213
be invalidated or altered.
1215
if self._returning == 'next':
1216
# We have to know the current nodes children to be able to list the
1217
# exclude keys for them. However, while we could have a second
1218
# look-ahead result buffer and shuffle things around, this method
1219
# is typically only called once per search - when memoising the
1220
# results of the search.
1221
found, ghosts, next, parents = self._do_query(self._next_query)
1222
# pretend we didn't query: perhaps we should tweak _do_query to be
1223
# entirely stateless?
1224
self.seen.difference_update(next)
1225
next_query = next.union(ghosts)
1227
next_query = self._next_query
1228
excludes = self._stopped_keys.union(next_query)
1229
included_keys = self.seen.difference(excludes)
1230
return SearchResult(self._started_keys, excludes, len(included_keys),
1236
except StopIteration:
1240
"""Return the next ancestors of this revision.
1242
Ancestors are returned in the order they are seen in a breadth-first
1243
traversal. No ancestor will be returned more than once. Ancestors are
1244
returned before their parentage is queried, so ghosts and missing
1245
revisions (including the start revisions) are included in the result.
1246
This can save a round trip in LCA style calculation by allowing
1247
convergence to be detected without reading the data for the revision
1248
the convergence occurs on.
1250
:return: A set of revision_ids.
1252
if self._returning != 'next':
1253
# switch to returning the query, not the results.
1254
self._returning = 'next'
1255
self._iterations += 1
1258
if len(self._next_query) == 0:
1259
raise StopIteration()
1260
# We have seen what we're querying at this point as we are returning
1261
# the query, not the results.
1262
self.seen.update(self._next_query)
1263
return self._next_query
1265
def next_with_ghosts(self):
1266
"""Return the next found ancestors, with ghosts split out.
1268
Ancestors are returned in the order they are seen in a breadth-first
1269
traversal. No ancestor will be returned more than once. Ancestors are
1270
returned only after asking for their parents, which allows us to detect
1271
which revisions are ghosts and which are not.
1273
:return: A tuple with (present ancestors, ghost ancestors) sets.
1275
if self._returning != 'next_with_ghosts':
1276
# switch to returning the results, not the current query.
1277
self._returning = 'next_with_ghosts'
1279
if len(self._next_query) == 0:
1280
raise StopIteration()
1282
return self._current_present, self._current_ghosts
1285
"""Advance the search.
1287
Updates self.seen, self._next_query, self._current_present,
1288
self._current_ghosts, self._current_parents and self._iterations.
1290
self._iterations += 1
1291
found, ghosts, next, parents = self._do_query(self._next_query)
1292
self._current_present = found
1293
self._current_ghosts = ghosts
1294
self._next_query = next
1295
self._current_parents = parents
1296
# ghosts are implicit stop points, otherwise the search cannot be
1297
# repeated when ghosts are filled.
1298
self._stopped_keys.update(ghosts)
1300
def _do_query(self, revisions):
1301
"""Query for revisions.
1303
Adds revisions to the seen set.
1305
:param revisions: Revisions to query.
1306
:return: A tuple: (set(found_revisions), set(ghost_revisions),
1307
set(parents_of_found_revisions), dict(found_revisions:parents)).
1309
found_revisions = set()
1310
parents_of_found = set()
1311
# revisions may contain nodes that point to other nodes in revisions:
1312
# we want to filter them out.
1313
self.seen.update(revisions)
1314
parent_map = self._parents_provider.get_parent_map(revisions)
1315
found_revisions.update(parent_map)
1316
for rev_id, parents in parent_map.iteritems():
1319
new_found_parents = [p for p in parents if p not in self.seen]
1320
if new_found_parents:
1321
# Calling set.update() with an empty generator is actually
1323
parents_of_found.update(new_found_parents)
1324
ghost_revisions = revisions - found_revisions
1325
return found_revisions, ghost_revisions, parents_of_found, parent_map
1330
def find_seen_ancestors(self, revisions):
1331
"""Find ancestors of these revisions that have already been seen.
1333
This function generally makes the assumption that querying for the
1334
parents of a node that has already been queried is reasonably cheap.
1335
(eg, not a round trip to a remote host).
1337
# TODO: Often we might ask one searcher for its seen ancestors, and
1338
# then ask another searcher the same question. This can result in
1339
# searching the same revisions repeatedly if the two searchers
1340
# have a lot of overlap.
1341
all_seen = self.seen
1342
pending = set(revisions).intersection(all_seen)
1343
seen_ancestors = set(pending)
1345
if self._returning == 'next':
1346
# self.seen contains what nodes have been returned, not what nodes
1347
# have been queried. We don't want to probe for nodes that haven't
1348
# been searched yet.
1349
not_searched_yet = self._next_query
1351
not_searched_yet = ()
1352
pending.difference_update(not_searched_yet)
1353
get_parent_map = self._parents_provider.get_parent_map
1355
parent_map = get_parent_map(pending)
1357
# We don't care if it is a ghost, since it can't be seen if it is
1359
for parent_ids in parent_map.itervalues():
1360
all_parents.extend(parent_ids)
1361
next_pending = all_seen.intersection(all_parents).difference(seen_ancestors)
1362
seen_ancestors.update(next_pending)
1363
next_pending.difference_update(not_searched_yet)
1364
pending = next_pending
1366
return seen_ancestors
1368
def stop_searching_any(self, revisions):
1370
Remove any of the specified revisions from the search list.
1372
None of the specified revisions are required to be present in the
1375
It is okay to call stop_searching_any() for revisions which were seen
1376
in previous iterations. It is the callers responsibility to call
1377
find_seen_ancestors() to make sure that current search tips that are
1378
ancestors of those revisions are also stopped. All explicitly stopped
1379
revisions will be excluded from the search result's get_keys(), though.
1381
# TODO: does this help performance?
1384
revisions = frozenset(revisions)
1385
if self._returning == 'next':
1386
stopped = self._next_query.intersection(revisions)
1387
self._next_query = self._next_query.difference(revisions)
1389
stopped_present = self._current_present.intersection(revisions)
1390
stopped = stopped_present.union(
1391
self._current_ghosts.intersection(revisions))
1392
self._current_present.difference_update(stopped)
1393
self._current_ghosts.difference_update(stopped)
1394
# stopping 'x' should stop returning parents of 'x', but
1395
# not if 'y' always references those same parents
1396
stop_rev_references = {}
1397
for rev in stopped_present:
1398
for parent_id in self._current_parents[rev]:
1399
if parent_id not in stop_rev_references:
1400
stop_rev_references[parent_id] = 0
1401
stop_rev_references[parent_id] += 1
1402
# if only the stopped revisions reference it, the ref count will be
1404
for parents in self._current_parents.itervalues():
1405
for parent_id in parents:
1407
stop_rev_references[parent_id] -= 1
1410
stop_parents = set()
1411
for rev_id, refs in stop_rev_references.iteritems():
1413
stop_parents.add(rev_id)
1414
self._next_query.difference_update(stop_parents)
1415
self._stopped_keys.update(stopped)
1416
self._stopped_keys.update(revisions)
1419
def start_searching(self, revisions):
1420
"""Add revisions to the search.
1422
The parents of revisions will be returned from the next call to next()
1423
or next_with_ghosts(). If next_with_ghosts was the most recently used
1424
next* call then the return value is the result of looking up the
1425
ghost/not ghost status of revisions. (A tuple (present, ghosted)).
1427
revisions = frozenset(revisions)
1428
self._started_keys.update(revisions)
1429
new_revisions = revisions.difference(self.seen)
1430
if self._returning == 'next':
1431
self._next_query.update(new_revisions)
1432
self.seen.update(new_revisions)
1434
# perform a query on revisions
1435
revs, ghosts, query, parents = self._do_query(revisions)
1436
self._stopped_keys.update(ghosts)
1437
self._current_present.update(revs)
1438
self._current_ghosts.update(ghosts)
1439
self._next_query.update(query)
1440
self._current_parents.update(parents)
1444
class SearchResult(object):
1445
"""The result of a breadth first search.
1447
A SearchResult provides the ability to reconstruct the search or access a
1448
set of the keys the search found.
1451
def __init__(self, start_keys, exclude_keys, key_count, keys):
1452
"""Create a SearchResult.
1454
:param start_keys: The keys the search started at.
1455
:param exclude_keys: The keys the search excludes.
1456
:param key_count: The total number of keys (from start to but not
1458
:param keys: The keys the search found. Note that in future we may get
1459
a SearchResult from a smart server, in which case the keys list is
1460
not necessarily immediately available.
1462
self._recipe = ('search', start_keys, exclude_keys, key_count)
1463
self._keys = frozenset(keys)
1465
def get_recipe(self):
1466
"""Return a recipe that can be used to replay this search.
1468
The recipe allows reconstruction of the same results at a later date
1469
without knowing all the found keys. The essential elements are a list
1470
of keys to start and to stop at. In order to give reproducible
1471
results when ghosts are encountered by a search they are automatically
1472
added to the exclude list (or else ghost filling may alter the
1475
:return: A tuple ('search', start_keys_set, exclude_keys_set,
1476
revision_count). To recreate the results of this search, create a
1477
breadth first searcher on the same graph starting at start_keys.
1478
Then call next() (or next_with_ghosts()) repeatedly, and on every
1479
result, call stop_searching_any on any keys from the exclude_keys
1480
set. The revision_count value acts as a trivial cross-check - the
1481
found revisions of the new search should have as many elements as
1482
revision_count. If it does not, then additional revisions have been
1483
ghosted since the search was executed the first time and the second
1489
"""Return the keys found in this search.
1491
:return: A set of keys.
1496
"""Return false if the search lists 1 or more revisions."""
1497
return self._recipe[3] == 0
1499
def refine(self, seen, referenced):
1500
"""Create a new search by refining this search.
1502
:param seen: Revisions that have been satisfied.
1503
:param referenced: Revision references observed while satisfying some
1506
start = self._recipe[1]
1507
exclude = self._recipe[2]
1508
count = self._recipe[3]
1509
keys = self.get_keys()
1510
# New heads = referenced + old heads - seen things - exclude
1511
pending_refs = set(referenced)
1512
pending_refs.update(start)
1513
pending_refs.difference_update(seen)
1514
pending_refs.difference_update(exclude)
1515
# New exclude = old exclude + satisfied heads
1516
seen_heads = start.intersection(seen)
1517
exclude.update(seen_heads)
1518
# keys gets seen removed
1520
# length is reduced by len(seen)
1522
return SearchResult(pending_refs, exclude, count, keys)
1525
class PendingAncestryResult(object):
1526
"""A search result that will reconstruct the ancestry for some graph heads.
1528
Unlike SearchResult, this doesn't hold the complete search result in
1529
memory, it just holds a description of how to generate it.
1532
def __init__(self, heads, repo):
1535
:param heads: an iterable of graph heads.
1536
:param repo: a repository to use to generate the ancestry for the given
1539
self.heads = frozenset(heads)
1542
def get_recipe(self):
1543
"""Return a recipe that can be used to replay this search.
1545
The recipe allows reconstruction of the same results at a later date.
1547
:seealso SearchResult.get_recipe:
1549
:return: A tuple ('proxy-search', start_keys_set, set(), -1)
1550
To recreate this result, create a PendingAncestryResult with the
1553
return ('proxy-search', self.heads, set(), -1)
1556
"""See SearchResult.get_keys.
1558
Returns all the keys for the ancestry of the heads, excluding
1561
return self._get_keys(self.repo.get_graph())
1563
def _get_keys(self, graph):
1564
NULL_REVISION = revision.NULL_REVISION
1565
keys = [key for (key, parents) in graph.iter_ancestry(self.heads)
1566
if key != NULL_REVISION and parents is not None]
1570
"""Return false if the search lists 1 or more revisions."""
1571
if revision.NULL_REVISION in self.heads:
1572
return len(self.heads) == 1
1574
return len(self.heads) == 0
1576
def refine(self, seen, referenced):
1577
"""Create a new search by refining this search.
1579
:param seen: Revisions that have been satisfied.
1580
:param referenced: Revision references observed while satisfying some
1583
referenced = self.heads.union(referenced)
1584
return PendingAncestryResult(referenced - seen, self.repo)
1587
def collapse_linear_regions(parent_map):
1588
"""Collapse regions of the graph that are 'linear'.
1594
can be collapsed by removing B and getting::
1598
:param parent_map: A dictionary mapping children to their parents
1599
:return: Another dictionary with 'linear' chains collapsed
1601
# Note: this isn't a strictly minimal collapse. For example:
1609
# Will not have 'D' removed, even though 'E' could fit. Also:
1615
# A and C are both kept because they are edges of the graph. We *could* get
1616
# rid of A if we wanted.
1624
# Will not have any nodes removed, even though you do have an
1625
# 'uninteresting' linear D->B and E->C
1627
for child, parents in parent_map.iteritems():
1628
children.setdefault(child, [])
1630
children.setdefault(p, []).append(child)
1632
orig_children = dict(children)
1634
result = dict(parent_map)
1635
for node in parent_map:
1636
parents = result[node]
1637
if len(parents) == 1:
1638
parent_children = children[parents[0]]
1639
if len(parent_children) != 1:
1640
# This is not the only child
1642
node_children = children[node]
1643
if len(node_children) != 1:
1645
child_parents = result.get(node_children[0], None)
1646
if len(child_parents) != 1:
1647
# This is not its only parent
1649
# The child of this node only points at it, and the parent only has
1650
# this as a child. remove this node, and join the others together
1651
result[node_children[0]] = parents
1652
children[parents[0]] = node_children