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# Copyright (C) 2006 by Canonical Ltd
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# # GNU General Public License for more details.
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
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from getpass import getpass
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from urlparse import urlsplit, urlunsplit
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import bzrlib.errors as errors
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export BZR_LP_XMLRPC_URL=http://xmlrpc.staging.launchpad.net/bazaar/
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class LaunchpadService(object):
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"""A service to talk to Launchpad via XMLRPC.
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See http://bazaar-vcs.org/Specs/LaunchpadRpc for the methods we can call.
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# NB: this should always end in a slash to avoid xmlrpclib appending
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DEFAULT_SERVICE_URL = 'https://xmlrpc.launchpad.net/bazaar/'
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registrant_email = None
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registrant_password = None
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def __init__(self, transport=None):
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"""Construct a new service talking to the launchpad rpc server"""
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uri_type = urllib.splittype(self.service_url)[0]
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if uri_type == 'https':
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transport = xmlrpclib.SafeTransport()
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transport = xmlrpclib.Transport()
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transport.user_agent = 'bzr/%s (xmlrpclib/%s)' \
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% (bzrlib.__version__, xmlrpclib.__version__)
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self.transport = transport
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def service_url(self):
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"""Return the http or https url for the xmlrpc server.
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This does not include the username/password credentials.
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key = 'BZR_LP_XMLRPC_URL'
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return os.environ[key]
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return self.DEFAULT_SERVICE_URL
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"""Return the proxy for XMLRPC requests."""
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# auth info must be in url
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# TODO: if there's no registrant email perhaps we should just connect
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scheme, hostinfo, path = urlsplit(self.service_url)[:3]
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assert '@' not in hostinfo
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assert self.registrant_email is not None
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assert self.registrant_password is not None
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# TODO: perhaps fully quote the password to make it very slightly
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# TODO: can we perhaps add extra Authorization headers directly to the
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# request, rather than putting this into the url? perhaps a bit more
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# secure against accidentally revealing it. std66 s3.2.1 discourages putting
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# the password in the url.
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hostinfo = '%s:%s@%s' % (urllib.quote(self.registrant_email),
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urllib.quote(self.registrant_password),
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url = urlunsplit((scheme, hostinfo, path, '', ''))
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return xmlrpclib.ServerProxy(url, transport=self.transport)
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def gather_user_credentials(self):
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"""Get the password from the user."""
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config = bzrlib.config.GlobalConfig()
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self.registrant_email = config.user_email()
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if self.registrant_password is None:
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prompt = 'launchpad.net password for %s: ' % \
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self.registrant_password = getpass(prompt)
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def send_request(self, method_name, method_params):
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proxy = self.get_proxy()
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method = getattr(proxy, method_name)
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result = method(*method_params)
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except xmlrpclib.ProtocolError, e:
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# TODO: This can give a ProtocolError representing a 301 error, whose
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# e.headers['location'] tells where to go and e.errcode==301; should
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# probably log something and retry on the new url.
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raise NotImplementedError("should resend request to %s, but this isn't implemented"
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% e.headers.get('Location', 'NO-LOCATION-PRESENT'))
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# we don't want to print the original message because its
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# str representation includes the plaintext password.
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# TODO: print more headers to help in tracking down failures
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raise errors.BzrError("xmlrpc protocol error connecting to %s: %s %s"
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% (self.service_url, e.errcode, e.errmsg))
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class BaseRequest(object):
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"""Base request for talking to a XMLRPC server."""
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# Set this to the XMLRPC method name.
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def _request_params(self):
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"""Return the arguments to pass to the method"""
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raise NotImplementedError(self._request_params)
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def submit(self, service):
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"""Submit request to Launchpad XMLRPC server.
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:param service: LaunchpadService indicating where to send
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the request and the authentication credentials.
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return service.send_request(self._methodname, self._request_params())
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class DryRunLaunchpadService(LaunchpadService):
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"""Service that just absorbs requests without sending to server.
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The dummy service does not need authentication.
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def send_request(self, method_name, method_params):
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def gather_user_credentials(self):
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class BranchRegistrationRequest(BaseRequest):
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"""Request to tell Launchpad about a bzr branch."""
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_methodname = 'register_branch'
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def __init__(self, branch_url,
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branch_description='',
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self.branch_url = branch_url
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self.branch_name = branch_name
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self.branch_name = self._find_default_branch_name(self.branch_url)
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self.branch_title = branch_title
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self.branch_description = branch_description
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self.author_email = author_email
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self.product_name = product_name
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def _request_params(self):
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"""Return xmlrpc request parameters"""
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# This must match the parameter tuple expected by Launchpad for this
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return (self.branch_url,
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self.branch_description,
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def _find_default_branch_name(self, branch_url):
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i = branch_url.rfind('/')
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return branch_url[i+1:]
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class BranchBugLinkRequest(BaseRequest):
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"""Request to link a bzr branch in Launchpad to a bug."""
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_methodname = 'link_branch_to_bug'
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def __init__(self, branch_url, bug_id):
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self.branch_url = branch_url
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def _request_params(self):
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"""Return xmlrpc request parameters"""
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# This must match the parameter tuple expected by Launchpad for this
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return (self.branch_url, self.bug_id, '')