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# (C) 2005, 2006 Canonical Limited.
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
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"""Topological sorting routines."""
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import bzrlib.errors as errors
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"""Topological sort a graph.
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graph -- sequence of pairs of node->parents_list.
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The result is a list of node names, such that all parents come before
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Nodes at the same depth are returned in sorted order.
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node identifiers can be any hashable object, and are typically strings.
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return TopoSorter(graph).sorted()
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class TopoSorter(object):
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def __init__(self, graph):
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"""Topological sorting of a graph.
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:param graph: sequence of pairs of node_name->parent_names_list.
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i.e. [('C', ['B']), ('B', ['A']), ('A', [])]
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For this input the output from the sort or
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iter_topo_order routines will be:
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node identifiers can be any hashable object, and are typically strings.
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If you have a graph like [('a', ['b']), ('a', ['c'])] this will only use
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one of the two values for 'a'.
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The graph is sorted lazily: until you iterate or sort the input is
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not processed other than to create an internal representation.
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iteration or sorting may raise GraphCycleError if a cycle is present
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# a dict of the graph.
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self._graph = dict(graph)
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# self._original_graph = dict(graph)
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# this is a stack storing the depth first search into the graph.
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self._node_name_stack = []
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# at each level of 'recursion' we have to check each parent. This
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# stack stores the parents we have not yet checked for the node at the
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# matching depth in _node_name_stack
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self._pending_parents_stack = []
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# this is a set of the completed nodes for fast checking whether a
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# parent in a node we are processing on the stack has already been
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# emitted and thus can be skipped.
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self._completed_node_names = set()
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"""Sort the graph and return as a list.
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After calling this the sorter is empty and you must create a new one.
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return list(self.iter_topo_order())
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### Useful if fiddling with this code.
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### sorted_names = list(self.iter_topo_order())
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### for index in range(len(sorted_names)):
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### rev = sorted_names[index]
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### for left_index in range(index):
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### if rev in self.original_graph[sorted_names[left_index]]:
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### print "revision in parent list of earlier revision"
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### import pdb;pdb.set_trace()
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def iter_topo_order(self):
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"""Yield the nodes of the graph in a topological order.
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After finishing iteration the sorter is empty and you cannot continue
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# now pick a random node in the source graph, and transfer it to the
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# top of the depth first search stack.
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node_name, parents = self._graph.popitem()
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self._push_node(node_name, parents)
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while self._node_name_stack:
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# loop until this call completes.
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parents_to_visit = self._pending_parents_stack[-1]
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# if all parents are done, the revision is done
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if not parents_to_visit:
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# append the revision to the topo sorted list
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# all the nodes parents have been added to the output, now
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# we can add it to the output.
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yield self._pop_node()
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while self._pending_parents_stack[-1]:
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# recurse depth first into a single parent
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next_node_name = self._pending_parents_stack[-1].pop()
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if next_node_name in self._completed_node_names:
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# this parent was completed by a child on the
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# call stack. skip it.
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# otherwise transfer it from the source graph into the
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# top of the current depth first search stack.
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parents = self._graph.pop(next_node_name)
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# if the next node is not in the source graph it has
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# already been popped from it and placed into the
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# current search stack (but not completed or we would
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# have hit the continue 4 lines up.
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# this indicates a cycle.
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raise errors.GraphCycleError(self._node_name_stack)
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self._push_node(next_node_name, parents)
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# and do not continue processing parents until this 'call'
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def _push_node(self, node_name, parents):
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"""Add node_name to the pending node stack.
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Names in this stack will get emitted into the output as they are popped
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self._node_name_stack.append(node_name)
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self._pending_parents_stack.append(list(parents))
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"""Pop the top node off the stack
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The node is appended to the sorted output.
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# we are returning from the flattened call frame:
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# pop off the local variables
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node_name = self._node_name_stack.pop()
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self._pending_parents_stack.pop()
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self._completed_node_names.add(node_name)