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# Copyright (C) 2005, 2006 Canonical
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
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# TODO: Some kind of command-line display of revision properties:
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# perhaps show them in log -v and allow them as options to the commit command.
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import bzrlib.errors as errors
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from bzrlib.graph import node_distances, select_farthest, all_descendants, Graph
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from bzrlib.osutils import contains_whitespace
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from bzrlib.progress import DummyProgress
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from bzrlib.symbol_versioning import (deprecated_function,
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from bzrlib.graph import farthest_nodes, node_distances, all_descendants
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class RevisionReference(object):
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Reference to a stored revision.
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Includes the revision_id and revision_sha1.
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def __init__(self, revision_id, revision_sha1=None):
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if revision_id == None \
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or isinstance(revision_id, basestring):
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self.revision_id = revision_id
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raise ValueError('bad revision_id %r' % revision_id)
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if revision_sha1 != None:
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if isinstance(revision_sha1, basestring) \
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and len(revision_sha1) == 40:
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self.revision_sha1 = revision_sha1
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raise ValueError('bad revision_sha1 %r' % revision_sha1)
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class Revision(object):
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After bzr 0.0.5 revisions are allowed to have multiple parents.
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List of parent revision_ids
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Dictionary of revision properties. These are attached to the
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revision as extra metadata. The name must be a single
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word; the value can be an arbitrary string.
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List of parent revisions, each is a RevisionReference.
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def __init__(self, revision_id, properties=None, **args):
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self.revision_id = revision_id
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self.properties = properties or {}
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self._check_properties()
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self.parent_sha1s = []
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"""Not used anymore - legacy from for 4."""
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def __init__(self, **args):
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self.__dict__.update(args)
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def __repr__(self):
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return "<Revision id %s>" % self.revision_id
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def __eq__(self, other):
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if not isinstance(other, Revision):
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# FIXME: rbc 20050930 parent_ids are not being compared
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self.inventory_sha1 == other.inventory_sha1
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return (self.inventory_id == other.inventory_id
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and self.inventory_sha1 == other.inventory_sha1
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and self.revision_id == other.revision_id
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and self.timestamp == other.timestamp
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and self.message == other.message
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and self.timezone == other.timezone
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and self.committer == other.committer
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and self.properties == other.properties)
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and self.committer == other.committer)
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def __ne__(self, other):
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return not self.__eq__(other)
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def _check_properties(self):
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"""Verify that all revision properties are OK."""
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for name, value in self.properties.iteritems():
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if not isinstance(name, basestring) or contains_whitespace(name):
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raise ValueError("invalid property name %r" % name)
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if not isinstance(value, basestring):
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raise ValueError("invalid property value %r for %r" %
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def get_history(self, repository):
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"""Return the canonical line-of-history for this revision.
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If ghosts are present this may differ in result from a ghost-free
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current_revision = self
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while current_revision is not None:
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reversed_result.append(current_revision.revision_id)
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if not len (current_revision.parent_ids):
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reversed_result.append(None)
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current_revision = None
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next_revision_id = current_revision.parent_ids[0]
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current_revision = repository.get_revision(next_revision_id)
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reversed_result.reverse()
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return reversed_result
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def get_summary(self):
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"""Get the first line of the log message for this revision.
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return self.message.split('\n', 1)[0]
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def is_ancestor(revision_id, candidate_id, branch):
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def validate_revision_id(rid):
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"""Check rid is syntactically valid for a revision id."""
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if not REVISION_ID_RE:
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REVISION_ID_RE = re.compile('[\w.-]+@[\w.-]+--?\d+--?[0-9a-f]+\Z')
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if not REVISION_ID_RE.match(rid):
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raise ValueError("malformed revision-id %r" % rid)
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def is_ancestor(revision_id, candidate_id, revision_source):
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"""Return true if candidate_id is an ancestor of revision_id.
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A false negative will be returned if any intermediate descendent of
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candidate_id is not present in any of the revision_sources.
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revisions_source is an object supporting a get_revision operation that
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behaves like Branch's.
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return (candidate_id in branch.repository.get_ancestry(revision_id))
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for ancestor_id, distance in iter_ancestors(revision_id, revision_source):
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if ancestor_id == candidate_id:
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def iter_ancestors(revision_id, revision_source, only_present=False):
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ancestors = (revision_id,)
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def old_common_ancestor(revision_a, revision_b, revision_source):
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"""Find the ancestor common to both revisions that is closest to both.
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from bzrlib.trace import mutter
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a_ancestors = find_present_ancestors(revision_a, revision_source)
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b_ancestors = find_present_ancestors(revision_b, revision_source)
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# a_order is used as a tie-breaker when two equally-good bases are found
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for revision, (a_order, a_distance) in a_ancestors.iteritems():
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if b_ancestors.has_key(revision):
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a_intersection.append((a_distance, a_order, revision))
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b_intersection.append((b_ancestors[revision][1], a_order, revision))
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mutter("a intersection: %r" % a_intersection)
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mutter("b intersection: %r" % b_intersection)
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a_closest = __get_closest(a_intersection)
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if len(a_closest) == 0:
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b_closest = __get_closest(b_intersection)
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assert len(b_closest) != 0
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mutter ("a_closest %r" % a_closest)
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mutter ("b_closest %r" % b_closest)
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if a_closest[0] in b_closest:
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elif b_closest[0] in a_closest:
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raise bzrlib.errors.AmbiguousBase((a_closest[0], b_closest[0]))
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def revision_graph(revision, revision_source):
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"""Produce a graph of the ancestry of the specified revision.
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:return: root, ancestors map, descendants map
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Return root, ancestors map, descendants map
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TODO: Produce graphs with the NULL revision as root, so that we can find
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a common even when trees are not branches don't represent a single line
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revision_source.lock_read()
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return _revision_graph(revision, revision_source)
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revision_source.unlock()
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def _revision_graph(revision, revision_source):
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"""See revision_graph."""
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from bzrlib.tsort import topo_sort
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graph = revision_source.get_revision_graph(revision)
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# mark all no-parent revisions as being NULL_REVISION parentage.
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for node, parents in graph.items():
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if len(parents) == 0:
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graph[node] = [NULL_REVISION]
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# add NULL_REVISION to the graph
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graph[NULL_REVISION] = []
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# pick a root. If there are multiple roots
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# this could pick a random one.
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topo_order = topo_sort(graph.items())
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# map the descendants of the graph.
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# and setup our set based return graph.
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for node in graph.keys():
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descendants[node] = {}
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for node, parents in graph.items():
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for parent in parents:
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descendants[parent][node] = 1
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ancestors[node] = set(parents)
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descendants[revision] = {}
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while len(lines) > 0:
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rev = revision_source.get_revision(line)
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parents = [p.revision_id for p in rev.parents]
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if len(parents) == 0:
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except bzrlib.errors.NoSuchRevision:
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if parents is not None:
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for parent in parents:
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if parent not in ancestors:
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new_lines.add(parent)
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if parent not in descendants:
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descendants[parent] = {}
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descendants[parent][line] = 1
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if parents is not None:
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ancestors[line] = set(parents)
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assert root not in descendants[root]
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assert root not in ancestors[root]
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return root, ancestors, descendants
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def combined_graph(revision_a, revision_b, revision_source):
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"""Produce a combined ancestry graph.
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Return graph root, ancestors map, descendants map, set of common nodes"""
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root, ancestors, descendants = revision_graph(
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revision_a, revision_source)
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root_b, ancestors_b, descendants_b = revision_graph(
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revision_b, revision_source)
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root, ancestors, descendants = revision_graph(revision_a, revision_source)
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root_b, ancestors_b, descendants_b = revision_graph(revision_b,
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if root != root_b:
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raise errors.NoCommonRoot(revision_a, revision_b)
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raise bzrlib.errors.NoCommonRoot(revision_a, revision_b)
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for node, node_anc in ancestors_b.iteritems():
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if node in ancestors:
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ancestors[node].update(node_anc)
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for node, node_dec in descendants_b.iteritems():
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if node not in descendants:
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descendants[node] = {}
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descendants[node] = set()
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descendants[node].update(node_dec)
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return root, ancestors, descendants, common
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def common_ancestor(revision_a, revision_b, revision_source,
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if None in (revision_a, revision_b):
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if NULL_REVISION in (revision_a, revision_b):
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# trivial optimisation
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if revision_a == revision_b:
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def common_ancestor(revision_a, revision_b, revision_source):
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pb.update('Picking ancestor', 1, 3)
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graph = revision_source.get_revision_graph_with_ghosts(
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[revision_a, revision_b])
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# convert to a NULL_REVISION based graph.
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ancestors = graph.get_ancestors()
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descendants = graph.get_descendants()
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common = set(graph.get_ancestry(revision_a)).intersection(
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set(graph.get_ancestry(revision_b)))
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descendants[NULL_REVISION] = {}
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ancestors[NULL_REVISION] = []
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for root in graph.roots:
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descendants[NULL_REVISION][root] = 1
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ancestors[root].append(NULL_REVISION)
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for ghost in graph.ghosts:
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# ghosts act as roots for the purpose of finding
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# the longest paths from the root: any ghost *might*
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# be directly attached to the root, so we treat them
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# ghost now descends from NULL
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descendants[NULL_REVISION][ghost] = 1
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# that is it has an ancestor of NULL
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ancestors[ghost] = [NULL_REVISION]
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# ghost is common if any of ghosts descendants are common:
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for ghost_descendant in descendants[ghost]:
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if ghost_descendant in common:
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common.add(NULL_REVISION)
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except errors.NoCommonRoot:
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raise errors.NoCommonAncestor(revision_a, revision_b)
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pb.update('Picking ancestor', 2, 3)
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distances = node_distances (descendants, ancestors, root)
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pb.update('Picking ancestor', 3, 2)
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farthest = select_farthest(distances, common)
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if farthest is None or farthest == NULL_REVISION:
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raise errors.NoCommonAncestor(revision_a, revision_b)
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root, ancestors, descendants, common = \
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combined_graph(revision_a, revision_b, revision_source)
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except bzrlib.errors.NoCommonRoot:
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raise bzrlib.errors.NoCommonAncestor(revision_a, revision_b)
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nodes = farthest_nodes(descendants, ancestors, root)
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raise bzrlib.errors.NoCommonAncestor(revision_a, revision_b)
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class MultipleRevisionSources(object):
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"""Proxy that looks in multiple branches for revisions."""
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assert len(args) != 0
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self._revision_sources = args
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def revision_parents(self, revision_id):
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for source in self._revision_sources:
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return source.revision_parents(revision_id)
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except (errors.WeaveRevisionNotPresent, errors.NoSuchRevision), e:
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def get_revision(self, revision_id):
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for source in self._revision_sources:
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return source.get_revision(revision_id)
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except errors.NoSuchRevision, e:
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except bzrlib.errors.NoSuchRevision, e:
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def get_revision_graph(self, revision_id):
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# we could probe incrementally until the pending
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# ghosts list stop growing, but its cheaper for now
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# to just ask for the complete graph for each repository.
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for source in self._revision_sources:
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ghost_graph = source.get_revision_graph_with_ghosts()
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graphs.append(ghost_graph)
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if not revision_id in graph.get_ancestors():
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if absent == len(graphs):
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raise errors.NoSuchRevision(self._revision_sources[0], revision_id)
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pending = set([revision_id])
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def find_parents(node_id):
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"""find the parents for node_id."""
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ancestors = graph.get_ancestors()
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return ancestors[node_id]
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raise errors.NoSuchRevision(self._revision_sources[0], node_id)
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# all the graphs should have identical parent lists
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node_id = pending.pop()
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result[node_id] = find_parents(node_id)
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for parent_node in result[node_id]:
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if not parent_node in result:
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pending.add(parent_node)
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except errors.NoSuchRevision:
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def get_revision_graph_with_ghosts(self, revision_ids):
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# query all the sources for their entire graphs
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# and then build a combined graph for just
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for source in self._revision_sources:
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ghost_graph = source.get_revision_graph_with_ghosts()
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graphs.append(ghost_graph.get_ancestors())
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for revision_id in revision_ids:
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if not revision_id in graph:
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if absent == len(graphs):
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raise errors.NoSuchRevision(self._revision_sources[0],
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pending = set(revision_ids)
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def find_parents(node_id):
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"""find the parents for node_id."""
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return graph[node_id]
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raise errors.NoSuchRevision(self._revision_sources[0], node_id)
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# all the graphs should have identical parent lists
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node_id = pending.pop()
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parents = find_parents(node_id)
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for parent_node in parents:
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if (parent_node not in pending and
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parent_node not in done):
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pending.add(parent_node)
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result.add_node(node_id, parents)
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except errors.NoSuchRevision:
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result.add_ghost(node_id)
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for source in self._revision_sources:
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for source in self._revision_sources:
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@deprecated_function(zero_eight)
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def get_intervening_revisions(ancestor_id, rev_id, rev_source,
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def get_intervening_revisions(ancestor_id, rev_id, rev_source,
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revision_history=None):
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"""Find the longest line of descent from maybe_ancestor to revision.
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Revision history is followed where possible.
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root, ancestors, descendants = revision_graph(rev_id, rev_source)
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if len(descendants) == 0:
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raise errors.NoSuchRevision(rev_source, rev_id)
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raise NoSuchRevision(rev_source, rev_id)
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if ancestor_id not in descendants:
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rev_source.get_revision(ancestor_id)
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raise errors.NotAncestor(rev_id, ancestor_id)
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raise bzrlib.errors.NotAncestor(rev_id, ancestor_id)
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root_descendants = all_descendants(descendants, ancestor_id)
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root_descendants.add(ancestor_id)
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if rev_id not in root_descendants:
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raise errors.NotAncestor(rev_id, ancestor_id)
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raise bzrlib.errors.NotAncestor(rev_id, ancestor_id)
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distances = node_distances(descendants, ancestors, ancestor_id,
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root_descendants=root_descendants)
added
removed
bzrlib/revision.py
