70
70
def __repr__(self):
71
71
return "<Revision id %s>" % self.revision_id
75
from bzrlib.xml import Element, SubElement
77
root = Element('revision',
78
committer = self.committer,
79
timestamp = '%.9f' % self.timestamp,
80
revision_id = self.revision_id,
81
inventory_id = self.inventory_id,
82
inventory_sha1 = self.inventory_sha1,
85
root.set('timezone', str(self.timezone))
88
msg = SubElement(root, 'message')
89
msg.text = self.message
93
pelts = SubElement(root, 'parents')
94
pelts.tail = pelts.text = '\n'
95
for rr in self.parents:
96
assert isinstance(rr, RevisionReference)
97
p = SubElement(pelts, 'revision_ref')
100
p.set('revision_id', rr.revision_id)
102
p.set('revision_sha1', rr.revision_sha1)
107
def from_element(cls, elt):
108
return unpack_revision(elt)
110
from_element = classmethod(from_element)
114
def unpack_revision(elt):
115
"""Convert XML element into Revision object."""
116
# <changeset> is deprecated...
117
if elt.tag not in ('revision', 'changeset'):
118
raise bzrlib.errors.BzrError("unexpected tag in revision file: %r" % elt)
120
rev = Revision(committer = elt.get('committer'),
121
timestamp = float(elt.get('timestamp')),
122
revision_id = elt.get('revision_id'),
123
inventory_id = elt.get('inventory_id'),
124
inventory_sha1 = elt.get('inventory_sha1')
127
precursor = elt.get('precursor')
128
precursor_sha1 = elt.get('precursor_sha1')
130
pelts = elt.find('parents')
134
assert p.tag == 'revision_ref', \
135
"bad parent node tag %r" % p.tag
136
rev_ref = RevisionReference(p.get('revision_id'),
137
p.get('revision_sha1'))
138
rev.parents.append(rev_ref)
142
prec_parent = rev.parents[0].revision_id
143
assert prec_parent == precursor
145
# revisions written prior to 0.0.5 have a single precursor
146
# give as an attribute
147
rev_ref = RevisionReference(precursor, precursor_sha1)
148
rev.parents.append(rev_ref)
150
v = elt.get('timezone')
151
rev.timezone = v and int(v)
153
rev.message = elt.findtext('message') # text of <message>
73
def __eq__(self, other):
74
if not isinstance(other, Revision):
76
return (self.inventory_id == other.inventory_id
77
and self.inventory_sha1 == other.inventory_sha1
78
and self.revision_id == other.revision_id
79
and self.timestamp == other.timestamp
80
and self.message == other.message
81
and self.timezone == other.timezone
82
and self.committer == other.committer)
84
def __ne__(self, other):
85
return not self.__eq__(other)
158
89
REVISION_ID_RE = None
131
yield ancestor, distance
192
132
new_ancestors.extend([p.revision_id for p in revision.parents])
193
133
ancestors = new_ancestors
137
def find_present_ancestors(revision_id, revision_source):
138
"""Return the ancestors of a revision present in a branch.
140
It's possible that a branch won't have the complete ancestry of
141
one of its revisions.
145
anc_iter = enumerate(iter_ancestors(revision_id, revision_source,
147
for anc_order, (anc_id, anc_distance) in anc_iter:
148
if not found_ancestors.has_key(anc_id):
149
found_ancestors[anc_id] = (anc_order, anc_distance)
150
return found_ancestors
153
def __get_closest(intersection):
156
for entry in intersection:
157
if entry[0] == intersection[0][0]:
158
matches.append(entry[2])
162
def old_common_ancestor(revision_a, revision_b, revision_source):
163
"""Find the ancestor common to both revisions that is closest to both.
165
from bzrlib.trace import mutter
166
a_ancestors = find_present_ancestors(revision_a, revision_source)
167
b_ancestors = find_present_ancestors(revision_b, revision_source)
170
# a_order is used as a tie-breaker when two equally-good bases are found
171
for revision, (a_order, a_distance) in a_ancestors.iteritems():
172
if b_ancestors.has_key(revision):
173
a_intersection.append((a_distance, a_order, revision))
174
b_intersection.append((b_ancestors[revision][1], a_order, revision))
175
mutter("a intersection: %r" % a_intersection)
176
mutter("b intersection: %r" % b_intersection)
178
a_closest = __get_closest(a_intersection)
179
if len(a_closest) == 0:
181
b_closest = __get_closest(b_intersection)
182
assert len(b_closest) != 0
183
mutter ("a_closest %r" % a_closest)
184
mutter ("b_closest %r" % b_closest)
185
if a_closest[0] in b_closest:
187
elif b_closest[0] in a_closest:
190
raise bzrlib.errors.AmbiguousBase((a_closest[0], b_closest[0]))
193
def revision_graph(revision, revision_source):
194
"""Produce a graph of the ancestry of the specified revision.
195
Return root, ancestors map, descendants map
197
TODO: Produce graphs with the NULL revision as root, so that we can find
198
a common even when trees are not branches don't represent a single line
205
descendants[revision] = {}
206
while len(lines) > 0:
210
rev = revision_source.get_revision(line)
211
parents = [p.revision_id for p in rev.parents]
212
if len(parents) == 0:
214
except bzrlib.errors.NoSuchRevision:
218
if parents is not None:
219
for parent in parents:
220
if parent not in ancestors:
221
new_lines.add(parent)
222
if parent not in descendants:
223
descendants[parent] = {}
224
descendants[parent][line] = 1
225
if parents is not None:
226
ancestors[line] = set(parents)
228
assert root not in descendants[root]
229
assert root not in ancestors[root]
230
return root, ancestors, descendants
232
def combined_graph(revision_a, revision_b, revision_source):
233
"""Produce a combined ancestry graph.
234
Return graph root, ancestors map, descendants map, set of common nodes"""
235
root, ancestors, descendants = revision_graph(revision_a, revision_source)
236
root_b, ancestors_b, descendants_b = revision_graph(revision_b,
239
raise bzrlib.errors.NoCommonRoot(revision_a, revision_b)
241
for node, node_anc in ancestors_b.iteritems():
242
if node in ancestors:
245
ancestors[node] = set()
246
ancestors[node].update(node_anc)
247
for node, node_dec in descendants_b.iteritems():
248
if node not in descendants:
249
descendants[node] = set()
250
descendants[node].update(node_dec)
251
return root, ancestors, descendants, common
253
def common_ancestor(revision_a, revision_b, revision_source):
255
root, ancestors, descendants, common = \
256
combined_graph(revision_a, revision_b, revision_source)
257
except bzrlib.errors.NoCommonRoot:
258
raise bzrlib.errors.NoCommonAncestor(revision_a, revision_b)
260
nodes = farthest_nodes(descendants, ancestors, root)
264
raise bzrlib.errors.NoCommonAncestor(revision_a, revision_b)
196
266
class MultipleRevisionSources(object):
267
"""Proxy that looks in multiple branches for revisions."""
197
268
def __init__(self, *args):
198
269
object.__init__(self)
199
270
assert len(args) != 0
206
277
except bzrlib.errors.NoSuchRevision, e:
281
def get_intervening_revisions(ancestor_id, rev_id, rev_source,
282
revision_history=None):
283
"""Find the longest line of descent from maybe_ancestor to revision.
284
Revision history is followed where possible.
286
If ancestor_id == rev_id, list will be empty.
287
Otherwise, rev_id will be the last entry. ancestor_id will never appear.
288
If ancestor_id is not an ancestor, NotAncestor will be thrown
290
root, ancestors, descendants = revision_graph(rev_id, rev_source)
291
if len(descendants) == 0:
292
raise NoSuchRevision(rev_source, rev_id)
293
if ancestor_id not in descendants:
294
rev_source.get_revision(ancestor_id)
295
raise bzrlib.errors.NotAncestor(rev_id, ancestor_id)
296
root_descendants = all_descendants(descendants, ancestor_id)
297
root_descendants.add(ancestor_id)
298
if rev_id not in root_descendants:
299
raise bzrlib.errors.NotAncestor(rev_id, ancestor_id)
300
distances = node_distances(descendants, ancestors, ancestor_id,
301
root_descendants=root_descendants)
303
def best_ancestor(rev_id):
305
for anc_id in ancestors[rev_id]:
307
distance = distances[anc_id]
310
if revision_history is not None and anc_id in revision_history:
312
elif best is None or distance > best[1]:
313
best = (anc_id, distance)
318
while next != ancestor_id:
320
next = best_ancestor(next)