70
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def __repr__(self):
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return "<Revision id %s>" % self.revision_id
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from bzrlib.xml import Element, SubElement
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root = Element('revision',
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committer = self.committer,
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timestamp = '%.9f' % self.timestamp,
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revision_id = self.revision_id,
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inventory_id = self.inventory_id,
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inventory_sha1 = self.inventory_sha1,
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root.set('timezone', str(self.timezone))
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msg = SubElement(root, 'message')
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msg.text = self.message
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pelts = SubElement(root, 'parents')
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pelts.tail = pelts.text = '\n'
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for rr in self.parents:
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assert isinstance(rr, RevisionReference)
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p = SubElement(pelts, 'revision_ref')
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p.set('revision_id', rr.revision_id)
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p.set('revision_sha1', rr.revision_sha1)
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def from_element(cls, elt):
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return unpack_revision(elt)
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from_element = classmethod(from_element)
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def unpack_revision(elt):
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"""Convert XML element into Revision object."""
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# <changeset> is deprecated...
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if elt.tag not in ('revision', 'changeset'):
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raise bzrlib.errors.BzrError("unexpected tag in revision file: %r" % elt)
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rev = Revision(committer = elt.get('committer'),
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timestamp = float(elt.get('timestamp')),
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revision_id = elt.get('revision_id'),
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inventory_id = elt.get('inventory_id'),
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inventory_sha1 = elt.get('inventory_sha1')
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precursor = elt.get('precursor')
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precursor_sha1 = elt.get('precursor_sha1')
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pelts = elt.find('parents')
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assert p.tag == 'revision_ref', \
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"bad parent node tag %r" % p.tag
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rev_ref = RevisionReference(p.get('revision_id'),
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p.get('revision_sha1'))
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rev.parents.append(rev_ref)
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prec_parent = rev.parents[0].revision_id
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assert prec_parent == precursor
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# revisions written prior to 0.0.5 have a single precursor
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# give as an attribute
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rev_ref = RevisionReference(precursor, precursor_sha1)
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rev.parents.append(rev_ref)
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v = elt.get('timezone')
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rev.timezone = v and int(v)
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rev.message = elt.findtext('message') # text of <message>
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def __eq__(self, other):
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if not isinstance(other, Revision):
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return (self.inventory_id == other.inventory_id
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and self.inventory_sha1 == other.inventory_sha1
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and self.revision_id == other.revision_id
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and self.timestamp == other.timestamp
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and self.message == other.message
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and self.timezone == other.timezone
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and self.committer == other.committer)
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def __ne__(self, other):
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return not self.__eq__(other)
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REVISION_ID_RE = None
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yield ancestor, distance
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new_ancestors.extend([p.revision_id for p in revision.parents])
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ancestors = new_ancestors
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def find_present_ancestors(revision_id, revision_source):
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"""Return the ancestors of a revision present in a branch.
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It's possible that a branch won't have the complete ancestry of
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one of its revisions.
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anc_iter = enumerate(iter_ancestors(revision_id, revision_source,
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for anc_order, (anc_id, anc_distance) in anc_iter:
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if not found_ancestors.has_key(anc_id):
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found_ancestors[anc_id] = (anc_order, anc_distance)
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return found_ancestors
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def __get_closest(intersection):
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for entry in intersection:
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if entry[0] == intersection[0][0]:
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matches.append(entry[2])
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def old_common_ancestor(revision_a, revision_b, revision_source):
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"""Find the ancestor common to both revisions that is closest to both.
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from bzrlib.trace import mutter
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a_ancestors = find_present_ancestors(revision_a, revision_source)
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b_ancestors = find_present_ancestors(revision_b, revision_source)
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# a_order is used as a tie-breaker when two equally-good bases are found
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for revision, (a_order, a_distance) in a_ancestors.iteritems():
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if b_ancestors.has_key(revision):
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a_intersection.append((a_distance, a_order, revision))
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b_intersection.append((b_ancestors[revision][1], a_order, revision))
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mutter("a intersection: %r" % a_intersection)
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mutter("b intersection: %r" % b_intersection)
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a_closest = __get_closest(a_intersection)
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if len(a_closest) == 0:
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b_closest = __get_closest(b_intersection)
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assert len(b_closest) != 0
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mutter ("a_closest %r" % a_closest)
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mutter ("b_closest %r" % b_closest)
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if a_closest[0] in b_closest:
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elif b_closest[0] in a_closest:
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raise bzrlib.errors.AmbiguousBase((a_closest[0], b_closest[0]))
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def revision_graph(revision, revision_source):
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"""Produce a graph of the ancestry of the specified revision.
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Return root, ancestors map, descendants map
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TODO: Produce graphs with the NULL revision as root, so that we can find
198
a common even when trees are not branches don't represent a single line
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descendants[revision] = {}
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while len(lines) > 0:
210
rev = revision_source.get_revision(line)
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parents = [p.revision_id for p in rev.parents]
212
if len(parents) == 0:
214
except bzrlib.errors.NoSuchRevision:
218
if parents is not None:
219
for parent in parents:
220
if parent not in ancestors:
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new_lines.add(parent)
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if parent not in descendants:
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descendants[parent] = {}
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descendants[parent][line] = 1
225
if parents is not None:
226
ancestors[line] = set(parents)
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assert root not in descendants[root]
229
assert root not in ancestors[root]
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return root, ancestors, descendants
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def combined_graph(revision_a, revision_b, revision_source):
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"""Produce a combined ancestry graph.
234
Return graph root, ancestors map, descendants map, set of common nodes"""
235
root, ancestors, descendants = revision_graph(revision_a, revision_source)
236
root_b, ancestors_b, descendants_b = revision_graph(revision_b,
238
assert root == root_b
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for node, node_anc in ancestors_b.iteritems():
241
if node in ancestors:
244
ancestors[node] = set()
245
ancestors[node].update(node_anc)
246
for node, node_dec in descendants_b.iteritems():
247
if node not in descendants:
248
descendants[node] = set()
249
descendants[node].update(node_dec)
250
return root, ancestors, descendants, common
252
def common_ancestor(revision_a, revision_b, revision_source):
253
root, ancestors, descendants, common = \
254
combined_graph(revision_a, revision_b, revision_source)
255
nodes = farthest_nodes(descendants, ancestors, root)
196
260
class MultipleRevisionSources(object):
261
"""Proxy that looks in multiple branches for revisions."""
197
262
def __init__(self, *args):
198
263
object.__init__(self)
199
264
assert len(args) != 0
206
271
except bzrlib.errors.NoSuchRevision, e:
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def get_intervening_revisions(ancestor_id, rev_id, rev_source,
276
revision_history=None):
277
"""Find the longest line of descent from maybe_ancestor to revision.
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Revision history is followed where possible.
280
If ancestor_id == rev_id, list will be empty.
281
Otherwise, rev_id will be the last entry. ancestor_id will never appear.
282
If ancestor_id is not an ancestor, NotAncestor will be thrown
284
root, ancestors, descendants = revision_graph(rev_id, rev_source)
285
if len(descendants) == 0:
286
raise NoSuchRevision(rev_source, rev_id)
287
if ancestor_id not in descendants:
288
rev_source.get_revision(ancestor_id)
289
raise bzrlib.errors.NotAncestor(rev_id, ancestor_id)
290
root_descendants = all_descendants(descendants, ancestor_id)
291
root_descendants.add(ancestor_id)
292
if rev_id not in root_descendants:
293
raise bzrlib.errors.NotAncestor(rev_id, ancestor_id)
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distances = node_distances(descendants, ancestors, ancestor_id,
295
root_descendants=root_descendants)
297
def best_ancestor(rev_id):
299
for anc_id in ancestors[rev_id]:
301
distance = distances[anc_id]
304
if revision_history is not None and anc_id in revision_history:
306
elif best is None or distance > best[1]:
307
best = (anc_id, distance)
312
while next != ancestor_id:
314
next = best_ancestor(next)