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# Copyright (C) 2005 Canonical Ltd
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# This program is free software; you can redistribute it and/or modify
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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# GNU General Public License for more details.
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
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# Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA 02111-1307 USA
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"""Tree classes, representing directory at point in time.
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from cStringIO import StringIO
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from bzrlib.trace import mutter, note
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from bzrlib.errors import BzrError, BzrCheckError
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from bzrlib.inventory import Inventory
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from bzrlib.osutils import appendpath, fingerprint_file
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"""Abstract file tree.
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There are several subclasses:
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* `WorkingTree` exists as files on disk editable by the user.
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* `RevisionTree` is a tree as recorded at some point in the past.
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Trees contain an `Inventory` object, and also know how to retrieve
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file texts mentioned in the inventory, either from a working
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directory or from a store.
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It is possible for trees to contain files that are not described
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in their inventory or vice versa; for this use `filenames()`.
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Trees can be compared, etc, regardless of whether they are working
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trees or versioned trees.
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def has_filename(self, filename):
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"""True if the tree has given filename."""
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raise NotImplementedError()
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def has_id(self, file_id):
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return self.inventory.has_id(file_id)
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def has_or_had_id(self, file_id):
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if file_id == self.inventory.root.file_id:
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return self.inventory.has_id(file_id)
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return iter(self.inventory)
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def id2path(self, file_id):
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return self.inventory.id2path(file_id)
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def kind(self, file_id):
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raise NotImplementedError("subclasses must implement kind")
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def _get_inventory(self):
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return self._inventory
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def get_file_by_path(self, path):
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return self.get_file(self._inventory.path2id(path))
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inventory = property(_get_inventory,
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doc="Inventory of this Tree")
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def _check_retrieved(self, ie, f):
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fp = fingerprint_file(f)
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if ie.text_size != None:
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if ie.text_size != fp['size']:
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raise BzrError("mismatched size for file %r in %r" % (ie.file_id, self._store),
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["inventory expects %d bytes" % ie.text_size,
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"file is actually %d bytes" % fp['size'],
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"store is probably damaged/corrupt"])
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if ie.text_sha1 != fp['sha1']:
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raise BzrError("wrong SHA-1 for file %r in %r" % (ie.file_id, self._store),
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["inventory expects %s" % ie.text_sha1,
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"file is actually %s" % fp['sha1'],
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"store is probably damaged/corrupt"])
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def print_file(self, file_id):
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"""Print file with id `file_id` to stdout."""
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sys.stdout.write(self.get_file_text(file_id))
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def filter_unversioned_files(self, paths):
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"""Filter out paths that are not versioned.
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:return: set of paths.
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# NB: we specifically *don't* call self.has_filename, because for
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# WorkingTrees that can indicate files that exist on disk but that
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pred = self.inventory.has_filename
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return set((p for p in paths if not pred(p)))
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class RevisionTree(Tree):
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"""Tree viewing a previous revision.
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File text can be retrieved from the text store.
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TODO: Some kind of `__repr__` method, but a good one
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probably means knowing the branch and revision number,
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or at least passing a description to the constructor.
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def __init__(self, branch, inv, revision_id):
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self._branch = branch
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self._weave_store = branch.weave_store
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self._inventory = inv
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self._revision_id = revision_id
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def get_weave(self, file_id):
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return self._weave_store.get_weave(file_id,
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self._branch.get_transaction())
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def get_file_lines(self, file_id):
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ie = self._inventory[file_id]
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weave = self.get_weave(file_id)
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return weave.get_lines(ie.revision)
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def get_file_text(self, file_id):
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return ''.join(self.get_file_lines(file_id))
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def get_file(self, file_id):
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return StringIO(self.get_file_text(file_id))
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def get_file_size(self, file_id):
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return self._inventory[file_id].text_size
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def get_file_sha1(self, file_id):
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ie = self._inventory[file_id]
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if ie.kind == "file":
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def is_executable(self, file_id):
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ie = self._inventory[file_id]
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if ie.kind != "file":
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return self._inventory[file_id].executable
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def has_filename(self, filename):
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return bool(self.inventory.path2id(filename))
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def list_files(self):
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# The only files returned by this are those from the version
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for path, entry in self.inventory.iter_entries():
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yield path, 'V', entry.kind, entry.file_id, entry
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def get_symlink_target(self, file_id):
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ie = self._inventory[file_id]
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return ie.symlink_target;
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def kind(self, file_id):
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return self._inventory[file_id].kind
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self._branch.lock_read()
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self._branch.unlock()
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class EmptyTree(Tree):
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self._inventory = Inventory()
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def get_symlink_target(self, file_id):
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def has_filename(self, filename):
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def kind(self, file_id):
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assert self._inventory[file_id].kind == "root_directory"
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return "root_directory"
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def list_files(self):
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def __contains__(self, file_id):
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return file_id in self._inventory
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def get_file_sha1(self, file_id):
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assert self._inventory[file_id].kind == "root_directory"
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######################################################################
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# TODO: Merge these two functions into a single one that can operate
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# on either a whole tree or a set of files.
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# TODO: Return the diff in order by filename, not by category or in
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# random order. Can probably be done by lock-stepping through the
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# filenames from both trees.
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def file_status(filename, old_tree, new_tree):
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"""Return single-letter status, old and new names for a file.
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The complexity here is in deciding how to represent renames;
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many complex cases are possible.
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old_inv = old_tree.inventory
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new_inv = new_tree.inventory
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new_id = new_inv.path2id(filename)
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old_id = old_inv.path2id(filename)
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if not new_id and not old_id:
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# easy: doesn't exist in either; not versioned at all
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if new_tree.is_ignored(filename):
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return 'I', None, None
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return '?', None, None
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# There is now a file of this name, great.
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# There is no longer a file of this name, but we can describe
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# what happened to the file that used to have
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# this name. There are two possibilities: either it was
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# deleted entirely, or renamed.
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if new_inv.has_id(old_id):
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return 'X', old_inv.id2path(old_id), new_inv.id2path(old_id)
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return 'D', old_inv.id2path(old_id), None
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# if the file_id is new in this revision, it is added
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if new_id and not old_inv.has_id(new_id):
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# if there used to be a file of this name, but that ID has now
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# disappeared, it is deleted
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if old_id and not new_inv.has_id(old_id):
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def find_renames(old_inv, new_inv):
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for file_id in old_inv:
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if file_id not in new_inv:
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old_name = old_inv.id2path(file_id)
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new_name = new_inv.id2path(file_id)
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if old_name != new_name:
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yield (old_name, new_name)