~bzr-pqm/bzr/bzr.dev

3641.3.29 by John Arbash Meinel
Cleanup the copyright headers
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# Copyright (C) 2008 Canonical Ltd
3641.3.1 by John Arbash Meinel
Bring in the btree_index and chunk_writer code and their tests.
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#
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# This program is free software; you can redistribute it and/or modify
3641.3.29 by John Arbash Meinel
Cleanup the copyright headers
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# it under the terms of the GNU General Public License as published by
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# the Free Software Foundation; either version 2 of the License, or
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# (at your option) any later version.
3641.3.1 by John Arbash Meinel
Bring in the btree_index and chunk_writer code and their tests.
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#
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# This program is distributed in the hope that it will be useful,
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# but WITHOUT ANY WARRANTY; without even the implied warranty of
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# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
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# GNU General Public License for more details.
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#
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# You should have received a copy of the GNU General Public License
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# along with this program; if not, write to the Free Software
4183.7.1 by Sabin Iacob
update FSF mailing address
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# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
3641.3.1 by John Arbash Meinel
Bring in the btree_index and chunk_writer code and their tests.
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#
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"""B+Tree index parsing."""
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4789.28.1 by John Arbash Meinel
Use StaticTuple as part of the builder process.
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from bzrlib import static_tuple
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3641.3.1 by John Arbash Meinel
Bring in the btree_index and chunk_writer code and their tests.
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def _parse_leaf_lines(bytes, key_length, ref_list_length):
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    lines = bytes.split('\n')
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    nodes = []
4789.28.1 by John Arbash Meinel
Use StaticTuple as part of the builder process.
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    as_st = static_tuple.StaticTuple.from_sequence
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    stuple = static_tuple.StaticTuple
3641.3.1 by John Arbash Meinel
Bring in the btree_index and chunk_writer code and their tests.
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    for line in lines[1:]:
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        if line == '':
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            return nodes
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        elements = line.split('\0', key_length)
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        # keys are tuples
4789.28.1 by John Arbash Meinel
Use StaticTuple as part of the builder process.
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        key = as_st(elements[:key_length]).intern()
3641.3.1 by John Arbash Meinel
Bring in the btree_index and chunk_writer code and their tests.
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        line = elements[-1]
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        references, value = line.rsplit('\0', 1)
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        if ref_list_length:
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            ref_lists = []
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            for ref_string in references.split('\t'):
4789.28.1 by John Arbash Meinel
Use StaticTuple as part of the builder process.
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                ref_list = as_st([as_st(ref.split('\0')).intern()
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                                  for ref in ref_string.split('\r') if ref])
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                ref_lists.append(ref_list)
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            ref_lists = as_st(ref_lists)
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            node_value = stuple(value, ref_lists)
3641.3.1 by John Arbash Meinel
Bring in the btree_index and chunk_writer code and their tests.
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        else:
4789.28.1 by John Arbash Meinel
Use StaticTuple as part of the builder process.
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            node_value = stuple(value, stuple())
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        # No need for StaticTuple here as it is put into a dict
3641.3.1 by John Arbash Meinel
Bring in the btree_index and chunk_writer code and their tests.
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        nodes.append((key, node_value))
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    return nodes
3641.3.18 by John Arbash Meinel
Start working on a compiled function for transforming
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def _flatten_node(node, reference_lists):
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    """Convert a node into the serialized form.
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    :param node: A tuple representing a node (key_tuple, value, references)
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    :param reference_lists: Does this index have reference lists?
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    :return: (string_key, flattened)
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        string_key  The serialized key for referencing this node
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        flattened   A string with the serialized form for the contents
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    """
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    if reference_lists:
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        # TODO: Consider turning this back into the 'unoptimized' nested loop
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        #       form. It is probably more obvious for most people, and this is
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        #       just a reference implementation.
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        flattened_references = ['\r'.join(['\x00'.join(reference)
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                                           for reference in ref_list])
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                                for ref_list in node[3]]
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    else:
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        flattened_references = []
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    string_key = '\x00'.join(node[1])
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    line = ("%s\x00%s\x00%s\n" % (string_key,
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        '\t'.join(flattened_references), node[2]))
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    return string_key, line